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slamgirl [31]
3 years ago
13

A balance is used to measure: mass weight volume density

Chemistry
2 answers:
Crank3 years ago
8 0
A balance is used to determine mass
grin007 [14]3 years ago
6 0

Once the unit of mass is defined, samples of matter can be compared to the unit and thus measured.

Comparing a sample of matter to the standard unit of mass, or to its subdivision the gram, can be done

on an equal-arm balance.

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In 1838, botanist Matthias Schleiden, determined that all plants are composed of cells. In 1839, anatomist Theodor Schwann propo
Margarita [4]

Answer:

This question is incomplete; the complete part is:

A) All cell have a cell wall.

B) All cell arise from pre-existing cells.

C) All cell are capable of photosynthesis.

D) All cell can develop into any other type of cell.

The answer is B

Explanation:

The commonly known universal theory proposed in 1838 took the contribution from three remarkable scientists namely: botanist Matthias Schleiden, anatomist Theodor Schwann and biologist Rudolph Virchow. According to the question, Mathias discovered that all plants are made of cells, Schwann determined that all animals are made of cells while Virchow determined that all living things are composed of cells.

However, in addition to Virchow's discovery, he also discovered and proposed that "All cell arise from pre-existing cells", which till date forms part of the three components of the cell theory. The three parts are:

- Cell is the fundamental and basic unit of all living things.

- All living things are made up of one or more cells

- All cells arise from pre-existing cells

6 0
3 years ago
Two moles of gas A spontaneously convert to 3 moles of gas b in a container where the temperature and pressure are held constant
erica [24]

At constant temperature and pressure, If the amount of gas increases to the given value, its volume also increases to 20.85L.

<h3>What is Avogadro's law?</h3>

Avogadro's law states that "equal volumes of all gases, at the same temperature and pressure, have the same number of molecules."

It is expressed as;

V₁/n₁ = V₂/n₂

Given the data in the question;

  • Initial amount of gas n₁ = 2moles
  • Initial volume v₁ = 13.9L
  • Final amount of gas n₁ = 3moles
  • Final volume v₂ = ?

V₁/n₁ = V₂/n₂

V₁n₂ = V₂n₁

V₂ = V₁n₂ / n₁

V₂ = (13.9L × 3moles) / 2moles

V₂ = 41.7molL / 2mol

V₂ = 20.85L

At constant temperature and pressure, If the amount of gas increases to the given value, its volume also increases to 20.85L.

Learn more about Avogadro's law here: brainly.com/question/15613065

#SPJ1

4 0
1 year ago
Analysis of the water content of a lake found in the desert showed that it contained 17.5 percent chloride ion, and has a densit
tankabanditka [31]

Answer:

The molarity is 6.0 M.

Explanation:

<em>The </em><em>concentration</em><em> of a solution is the amount of solute present in a given amount  of solvent, or a given amount of solution.</em>

In this problem, we are asked to convert percent by mass to molarity, which are two different concentration units.

<em>The </em><em>percent by mass </em><em>is the ratio of the mass of a solute to the mass of the solution, multiplied by 100 percent.</em> On the other hand, <em>molarity (M)</em><em> is defined as the number of moles of solute per liter of solution.</em>

If we have 17.15 percent chloride ion, that means that we have 17.15 grams of chloride ion in 100 grams of solution. The density provided is the density of the solution, so we calculate how many mL correspond to 100 grams of solution:

1.23 g ----------- 1 mL

100 g ------------ <u>x= 81.3 mL</u>

Therefore, 17.5 grams of chloride ion are contained in 81.3 mL. Now we need to convert these grams into moles.

The atomic mass of chlorine is 35.5 g/mol:

35.5 g --------------- 1 mol

17.5 g --------------- <u>x= 0. 49 mol</u>

This 0.49 moles are contained in 81.13 mL, the definition of molarity says that this moles are contained in a liter (or what is the same, 1000 mL):

81.3 mL --------------- 0.49 mol

1000 mL ------------- x= 6.0 M

The molarity of the chloride ion will be 6.0 M.

5 0
3 years ago
4 g of ag2so4 will dissolve in 1l of water. calculate the solubility product (ksp) for silver (i) sulfate.
Bas_tet [7]
Reaction of dissociation: Ag₂SO₄ → 2Ag⁺ + SO₄²⁻.
m(Ag₂SO₄) = 4 g.
V(Ag₂SO₄) = 1 l.
n(Ag₂SO₄) = m(Ag₂SO₄) ÷ M(Ag₂SO₄).
n(Ag₂SO₄) = 4 g ÷ 311,8 g/mol.
n(Ag₂SO₄) = 0,0128 mol.
n(Ag⁺) = 2 · 0,0128 mol = 0,0256 mol.
n(Ag₂SO₄) = n(SO₄²⁻) = 0,0128 mol.
c(Ag⁺) = n ÷ V = 0,0256 mol ÷ 1 l = 0,0256 mol/l.
Ksp = c(Ag⁺)² · c(SO₄²⁻).
Ksp = (0,0256 mol/l)² · 0,0128 mol/l.
Ksp = 8,3·10⁻⁶.

7 0
3 years ago
This graph shows two curves pertaining to a hydrogen s orbital.
fgiga [73]

Answer 1) : According to the complete question attached in the answer,

The radial wave function  which is denoted by R_{nl}(r) shown with orange color crosses through zero point. Also, At the the radial nodes, which are spherical shells to some radial distance away from the nucleus there no electron are found.

Also, the radial probability distribution curve denoted as R^{2}_{nl}(r) shown in  blue  color is observed to touch zero, and shows the place of radial node.

Therefore, the total number of nodes will include both the kinds  which has radial and angular nodes which will be represented by <em>'n'</em>.

It is observed that for any atomic orbital, the total number of nodes will be n-1  .


Considering the s orbital of the hydrogen, which has zero angular momentum  (l); (l=0), as it has zero angular nodes.  

Hence, there will be only radial nodes, which is

(n−1  =  total number of radial nodes in s orbitals)

According to the image, there are 4  radial nodes shown, so n  =  5  (as n-1 = 4; therefore, n = 5)

This represents the 5s orbital.


Answer 2) The radial nodes are observed in I'm seeing radial nodes at  

1.9a_{0},  6.4a_{0},13.9a_{0} and  27.0a_{0}.

where  a_{0} represents the  hydorgen bohr atomic radius =  0.0529177 nm


Explanation : It is quite easy to observe the given graph and find out the approximate values of the radial nodes, it does not requires any equation to be solved. Equation can be used to find the radial nodes if it was supplied along with the question. Although by mere speculation one can find out the answer.

3 0
3 years ago
Read 2 more answers
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