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Nadusha1986 [10]
3 years ago
6

What is the molar mass of 37.96 g of gas exerting a pressure of 3.29 on the walls of a 4.60 L container at 375 K?

Chemistry
1 answer:
Phantasy [73]3 years ago
8 0

The molar mass of the gas is 77.20 gm/mole.

Explanation:

The data given is:

P = 3.29 atm,   V= 4.60 L   T= 375 K  mass of the gas = 37.96 grams

Using the ideal Gas Law will give the number of moles of the gas. The formula is

PV= nRT    (where R = Universal Gas Constant 0.08206 L.atm/ K mole

Also number of moles is not given so applying the formula

n= mass ÷ molar mass of one mole of the gas.

n = m ÷ x   ( x  molar mass) ( m mass given)

Now putting the values in Ideal Gas Law equation

PV = m ÷ x RT

3.29 × 4.60 = 37.96/x × 0.08206 × 375

15.134 = 1168.1241  ÷ x

15.134x = 1168.1241

x = 1168.1241 ÷ 15.13

x = 77.20 gm/mol

If all the units in the formula are put will get cancel only grams/mole will be there. Molecular weight is given by gm/mole.

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andreev551 [17]

Answer:

An ionic bond is the bonding between a non-metal and a metal, that occurs when charged atoms (ions) attract.

Explanation:

Here I put the function of Iconic Bond.

  • <em>Ionic bonds form so that the outermost energy level of atoms are filled. Ion. an atom or group of atoms that bring out a positive or negative electric charge as a result of having lost or gained one or more electrons.</em>

<em>Therefore, I hope this helps!</em>

7 0
2 years ago
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If 3.5 grams of NaN3 decomposed, how many grams of N2 would be produced?
Wewaii [24]

Answer:

5.25 moles.

Explanation:

The decomposition reaction of NaN₃ is as follows :

2NaN_3(s)\rightarrow 2Na(s)+3N_2(g)

We need to find how many grams of N₂ produced in the process.

From the above balanced chemical reaction, we conclude that the ratio of moles of sodium azide and nitrogen gas are 2 : 3.

2 moles of sodium azide decomposes to give 3 moles of nitrogen gas. So,

3.5 moles of sodium azide decomposes to give \dfrac{3}{2}\times 3.5=5.25 moles of nitrogen gas.

Hence, the number of moles produced is 5.25 moles.

6 0
3 years ago
Cu + 2AgNO3 es002-1.jpg 2Ag + Cu(NO3)2 How many moles of copper must react to form 0.854 mol Ag?
marin [14]
Balance Chemical Equation is as follow,

<span>                        Cu + 2 AgNO</span>₃     →    2 Ag + Cu(NO₃)₂

According to Balance Equation,

                   2 Moles of Ag is produced by reacting  =  1 Mole of Cu
So, 
     0.854 Moles of Ag will be produced by reacting  =  X Moles of Cu

Solving for X,
                             X  =  (0.854 mol × 1 mol) ÷ 2 mol

                             X  =  0.427 Moles of Cu
Result:
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are produced by reacting 0.427 Moles of Cu.
4 0
3 years ago
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Answer:

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C 20.4/12 = 1.7

O 70.4-16.0/16=3.4

CO2 1.7 mol * 44 = 74.8

3 0
3 years ago
The table describes how some substances were formed.
Tanzania [10]

R is the mixture formed by adding 5 g of sugar to 1 L of water.

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A mixture is an impure substance made up of two or more substances which are miscible or immiscible in each other.

Dissolving the sugar in the water makes a homogenous mixture and once dissolved a solution is made by the combination of a solute (sugar) and solvent (water).

Hence, R is the mixture formed by adding 5 g of sugar to 1 L of water.

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here:brainly.com/question/17247700

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7 0
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