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3 years ago

Which of the following words/phrases correctly describe(s) sugar water? Select all that apply.

Chemistry

1 answer:

Paul [167]3 years ago

6 0

Answer:

Heterogeneous mixture solution

Explanation:

The reason this is Heterogeneous is that you cant see each individual compound in the solution. If this was sand or any compund that is not desolvable or not fully desolved in water would be Homogenous since you can see the individual compounds (water and sand)

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Why do particles settle down in suspension

fomenos

No nkomkooehruurururuu is

6 0

2 years ago

4Fe + 30₂ ⇒ Fe₂0₃

DaniilM [7]

Answer:

The nuber of each one should be same

5 0

1 year ago

Please Help Quick!!!<br><br> Lewis Structure of PO3 3-

nevsk [136]

1. Find its coordination figure/coordination number of central atom (CF)

Ev = Vallence electron of central atom

Σe = electrons donated from substituents

Terminal O gives 0 electrons, hence Σe = 3 x 0

charge = charge of the compound

2. Find EP (electron pairs) and LP (lone pairs)

LP = CF - EP

3. Draw the skeleton with octet substituents (top right figure)

4. Find formal charge for each atoms (Qf)

5. Write formal charge near atom in skeleton

6. Enjoy

8 0

2 years ago

The temperature of a sample of water changes from 10°C to 20°C when the water absorbs 100 calories of heat. What is the mass of

Vlad1618 [11]

Answer:

10 g

Explanation:

Right from the start, just by inspecting the values given, you can say that the answer will be

10 g

Now, here's what that is the case.

As you know, a substance's specific heat tells you how much heat is needed to increase the temperature of

1 g

of that substance by

∘

Water has a specific heat of approximately

4.18

∘

. This tells you that in order to increase the temperature of

1 g

of water by

∘

, you need to provide

4.18 J

of heat.

Now, how much heat would be required to increase the temperature of

1 g

of water by

∘

Well, you'd need

4.18 J

to increase it by

∘

, another

4.18 J

to increase it by another

∘

, and so on. This means that you'd need

4.18 J

41.8 J

to increase the temperature of

1 g

of water by

∘

Now look at the value given to you. If you need

41.8 J

to increase the temperature of

1 g

of water by

∘

, what mass of water would require

times as much heat to increase its temperature by

∘

1 g

10 g

And that's your answer.

Mathematically, you can calculate this by using the equation

⋅

, where

- heat absorbed/lost

- the mass of the sample

- the specific heat of the substance

- the change in temperature, defined as final temperature minus initial temperature

Plug in your values to get

418

⋅

4.18

∘

⋅

(

−

)

∘

418

4.18

⋅

10 g

5 0

2 years ago

Calculate ΔH for the reaction: C(graphite) + 2H 2(g) + 1/2 O 2(g) => CH 3OH(l) Using the following information: C(graphite) +

Alika [10]

Answer:

$\Delta H$ for the given reaction is -238.7 kJ

Explanation:

The given reaction can be written as summation of three elementary steps such as:

$C(graphite)+O_{2}(g)\rightarrow CO_{2}(g)$ $\Delta H_{1}= -393.5 kJ$

$2H_{2}(g)+O_{2}(g)\rightarrow 2H_{2}O(l)$ $\Delta H_{2}= (2\times -285.8)kJ$

$CO_{2}(g)+2H_{2}O(l)\rightarrow CH_{3}OH(l)+\frac{3}{2}O_{2}(g)$ $\Delta H_{3}= 726.4 kJ$

---------------------------------------------------------------------------------------------------

$C(graphite)+2H_{2}(g)+\frac{1}{2}O_{2}(g)\rightarrow CH_{3}OH(l)$

$\Delta H=\Delta H_{1}+\Delta H_{2}+\Delta H_{3}=-238.7 kJ$

4 0

3 years ago