The midpoint of the segment with endpoints (-3,6) and (3, 0) is (0, 3)
<h3>Midpoint of a line </h3>
From the question, we are to determine the midpoint of the segment with the given endpoints
The given endpoints are
(-3,6) and (3, 0)
Given a line with endpoints (x₁, y₁) and (x₂, y₂), then the midpoint of the line is
((x₁+x₂)/2, (y₁+y₂)/2)
Thus,
The midpoint of the line with the endpoints (-3,6) and (3, 0) is
((-3+3)/2, (6+0/2)
= (0/2, 6/2)
= (0, 3)
Hence, the midpoint of the segment with endpoints (-3,6) and (3, 0) is (0, 3)
Learn more on Midpoint of a line here: brainly.com/question/18315903
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Which ones? which months?
38.44 billion cm, convert 238,900 mi to cm
cos(2<em>θ</em>) + sin²(<em>θ</em>) = 0
Half-angle identity:
cos(2<em>θ</em>) + (1 - cos(2<em>θ</em>))/2 = 0
Simplify:
2 cos(2<em>θ</em>) + 1 - cos(2<em>θ</em>) = 0
cos(2<em>θ</em>) = -1
Solve for <em>θ</em> :
2<em>θ</em> = arccos(-1) + 2<em>nπ</em>
2<em>θ</em> = <em>π</em> + 2<em>nπ</em>
<em>θ</em> = <em>π</em>/2 + <em>nπ</em>
where <em>n</em> is any integer.
