Ask question

Ask question

All categories

3 years ago

5

A 0.500 kg mass is oscillating on a

1 answer:

Norma-Jean [14]3 years ago

6 0

Answer:

3.6m/s

Explanation:

The following data were obtained from the question:

Mass (m) = 0.5Kg

Spring constant (K) = 330N/m

Energy = 3.24J

Velocity (v) =..?

The velocity of the mass can be obtained as follow:

E = ½mv²

3.24 = ½ × 0.5 × v²

3.24 = 0.25 × v²

Divide both side by 0.25

v² = 3.24/0.25

Take the square root of both side

v = √(3.24/0.25)

v = 3.6m/s

Therefore, the speed of the mass is 3.6m/s

You might be interested in

s person is deciding whether to install solar panels on her house. lt and explain three pieces of info she needs to consider to

Marrrta [24]

Efficiency- How much energy is wasted and how much useful energy is produced
Money- How expensive to install them
Location- She has to consider the location where she places them so that there is enough sunlight and light energy for the solar panels, obviously she should have solar panels if the location receives a sufficient amount of sunlight

8 0

4 years ago

A space rocket is launched and accelerates uniformly to 160 m/s in 4.5 s. Calculate the acceleration of the rocket.

-BARSIC- [3]

Answer:

<h2>35.56 m/s²</h2>

Explanation:

The acceleration of an object given it's velocity and time taken can be found by using the formula

$a = \frac{v}{t} \\$

v is the velocity

t is the time

From the question we have

$a = \frac{160}{4.5} = 35.55555...$

We have the final answer as

<h3>35.56 m/s²</h3>

Hope this helps you

6 0

3 years ago

An 8.75 kg point mass and a 14.0 kg point mass are held in place 50.0 cm apart. A particle of mass m is released from a point be

marysya [2.9K]

Answer

given,

mass of the = m₁ = 8.75 Kg

another mass of the object = m₂ = 14 Kg

distance between them = 50 cm

R₁ = 17 cm

R₂ = 50 -17 = 33 cm

a) Force applied due to the Mass 8.75 in +ve x- direction

$F_1 = \dfrac{GM_1 m}{R_1^2}$

$F_1 = \dfrac{6.67\times 10^{-11} \times 8.75\ m}{0.17^2}$

$F_1 = 2.019\times 10^{8}\ m$

Force applied due to mass 14 Kg in -ve x-direction

$F_2 = \dfrac{GM_2 m}{R_2^2}$

$F_2 = \dfrac{6.67\times 10^{-11} \times 14\ m}{0.33^2}$

$F_2 = 0.857\times 10^{8}\ m$

net force

F = F₁ + F₂

$F = 2.019\times 10^{8}\ m - 0.857\times 10^{8}\ m$

$F = 1.162\times 10^{8}\ m$

Using newton second law

$a = \dfrac{F}{m}$

$a = \dfrac{ 1.162\times 10^{8}\ m}{m}$

$a =1.162\times 10^{8} \ m/s^2$

b) As the acceleration of mass comes out to be +ve hence, the direction will be toward the mass of 8.75 Kg

6 0

4 years ago

On your way to work about two hours after sunrise, you notice the moon setting. What phase is it in?

Naily [24]

The moon setting on your way to work about two hours after sunrise means it is in the gibbous phase.

<h3>What is Gibbous phase?</h3>

This phase of the moon involves its side facing the Earth appearing more than half-lit by the Sun, but is less than fully lit.

This phase occurs few hours after sunrise usually in the early morning which is why it is the most appropriate choice.

Read more about Gibbous phase here brainly.com/question/3729811

#SPJ1

6 0

2 years ago

PLS HELP FAST!!!!!!!

Elan Coil [88]

Answer:D

Explanation:

6 0

2 years ago

Read 2 more answers