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castortr0y [4]
3 years ago
6

A baseball fan is 150.0 m from the home plate. how much time elapses between the instant the fan sees the batter hit the ball an

d the moment the fan hears the sound? assume t = 20.0oc.
Physics
1 answer:
Artyom0805 [142]3 years ago
7 0

Approximately 0.4373 seconds

Speed of sound at 20 degree C is roughly 343 meters/second

Speed of light = 3x10^8 or 300,000,000 meters/second

at 150.0 feet away you set it up as:

150.0/343 - 150/3x10^8

150.0/343 = 0.43731778

150/3x10^8 = 5x10^-7 or 0.0000005

Subtract 0.43731778 - 0.0000005

Answer is 0.43731728

Rounding would be approx. 0.4373

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Answer:

(a) F_{net} = 4.19 x 10^{-5} N, and its direction is towards m_{2}.

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Explanation:

Let, m_{1} = 165 kg, m_{2} = 465 kg, m_{3} = 60 kg, and the distance between m_{1} and m_{2} is 0.340 m.

(a) Since m_{3} is placed midway between m_{1} and m_{2}, then its distance to both masses is 0.170 m.

From the Newton's law of universal gravitation,

F = \frac{Gm_{1}m_{2}  }{r^{2} }

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Then,

a. F_{net} = F_{23} - F_{13}

F_{13} = \frac{6.67*10^{-11}*165*60 }{(0.17)^{2} }

     = 2.25 x 10^{-5} N

F_{23} = \frac{6.67*10^{-11}*465*60 }{(0.17)^{2} }

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∴ F_{net} =  = 6.44 x 10^{-5} - 2.25 x 10^{-5}

              = 4.19 x 10^{-5} N

The net force exerted by the two masses on the 60 kg object is 4.19 x 10^{-5}  N.

(ii) /F_{net}/ = /F_{23}/ - /F_{13}/

              = 6.44 x 10^{-5} - 2.25 x 10^{-5}

              = 4.19 x 10^{-5} N

(iii) The direction of the net force is to the right i.e towards m_{2}.

(b) For the net force experienced by the 60 kg object to be zero, it must be placed inside a hollow shell.

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