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castortr0y [4]
2 years ago
6

A baseball fan is 150.0 m from the home plate. how much time elapses between the instant the fan sees the batter hit the ball an

d the moment the fan hears the sound? assume t = 20.0oc.
Physics
1 answer:
Artyom0805 [142]2 years ago
7 0

Approximately 0.4373 seconds

Speed of sound at 20 degree C is roughly 343 meters/second

Speed of light = 3x10^8 or 300,000,000 meters/second

at 150.0 feet away you set it up as:

150.0/343 - 150/3x10^8

150.0/343 = 0.43731778

150/3x10^8 = 5x10^-7 or 0.0000005

Subtract 0.43731778 - 0.0000005

Answer is 0.43731728

Rounding would be approx. 0.4373

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What affects sounds at their source? MENTION DOPPLER EFFECT AND VIBRATIONS
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Answer:

Doppler effect, the apparent difference between the frequency at which sound or light waves leave a source and that at which they reach an observer, caused by relative motion of the observer and the wave source. This phenomenon is used in astronomical measurements, in Mössbauer effect studies, and in radar and modern navigation.

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B) A & C

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3 years ago
You are trying to overhear a most interesting conversation, but from your distance of 10.0 m , it sounds like only an average wh
Alexandra [31]

Answer:

r₂=0.1 m

Explanation:

Given that

r₁= 10 m  , β₁ = 20 dB

At r₂ ,β₂= 60 dB

As we know that intensity level of sound given as

\beta =10\ log\dfrac{I}{10^{-12}}

\beta _1=10\ log\dfrac{I_1}{10^{-12}}

20=10\ log\dfrac{I_1}{10^{-12}}

10² x 10⁻¹² = I₁

I₁=10⁻¹⁰ W/m²

\beta _2=10\ log\dfrac{I_2}{10^{-12}}

60=10\ log\dfrac{I_1}{10^{-12}}

10⁶ x  10⁻¹² = I₂

I₂ = 10⁻⁶ W/m²

I₁=10⁻¹⁰ W/m²

P = I A

P=Power ,I =Intensity  ,A=Area

\dfrac{I_1}{I_2}=\dfrac{r^2_2}{r^2_1}

\dfrac{10^{-10}}{10^{-6}}=\dfrac{r^2_2}{10^2}

r₂=0.1 m

4 0
2 years ago
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