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3 years ago

A decrease in the magnitude of velocity is called

Physics

1 answer:

ololo11 [35]3 years ago

5 0

That's called an "acceleration" or "slowing down".

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What is required to specify the position of an object?(๑•ᴗ•๑)♡

Mkey [24]

Answer:

Explanation:

To describe the motion of any object, we must be able to describe its position x. It reflects it at any particular time. In other words, we need to specify its position relative to the conventional frame of reference.

I hope it helps! ≧◉◡◉≦

8 0

2 years ago

Water (rhoH20 = 1000.0 kg/m3 ) flows through a garden hose that goes up a step 20.0 cm high. The cross-sectional area of the hos

Soloha48 [4]

Answer:

P₂ = 138.88 10³ Pa

Explanation:

This is a problem of fluid mechanics, we must use the continuity and Bernoulli equation

Let's start by looking for the top speed

Q = A₁ v₁ = A₂ v₂

We will use index 1 for the lower part and index 2 for the upper part, let's look for the speed in the upper part (v2)

v₂ = A₁ / A₂ v₁

They indicate that A₂ = ½ A₁ and give the speed at the bottom (v₁ = 1.20 m/s)

v₂ = 2 1.20

v₂ = 2.40 m / s

Now let's write the Bernoulli equation

P₁ + ½ ρ v₁² + ρ g y₁ = P2 + ½ ρ v₂² + ρ g y₂

Let's clear the pressure at point 2

P₂ = P₁ + ½ ρ (v₁² - v₂²) + ρ g (y₁-y₂)

we put our reference system at the lowest point

y₁ - y₂ = -20 cm

Let's calculate

P₂ = 143 10³ + ½ 1000 (1.20² - 2.40²) + 1000 9.8 (-0.200)

P₂ = 143 103 - 2,160 103 - 1,960 103

P₂ = 138.88 10³ Pa

3 0

3 years ago

12. A car traveling at 224 mis skids to a stop in 255 , Determine the<br> acceleration of the car.

Studentka2010 [4]

The difference between the two numbers is 31.

I didn’t quite understand your question, perhaps typos?

5 0

3 years ago

Select all that apply.

SpyIntel [72]

Answer:

Determine how to separate gasoline from other substances in petroleum

5 0

3 years ago

In a standard tensile test a steel rod of 22-mm diameter is subjected to a tension force of 75kN. Knowing that v = 0.30 and E =

Mazyrski [523]

Answer:

(a) Elongation of rod = 0.19732 mm

(b) Change in diameter = 0.00651 mm

Explanation:

Circular area at end of steel rod = pi * diameter^2 / 4

$Area = pi * (22 * 10^-^3)/4$

Area = 3.801 * 10^(-4) meter squared

Stress = force / area

Stress = 75000 / (3.801 * 10^-4)

Stress = 197316495 Pa OR 0.197 GPa

Modulus of elasticity = stress / strain

200 = 0.19732 / Strain

Strain = 0.0009866 (longitudinal)

(a) Strain = change in length / initial length

0.0009866 = Elongation of rod / 200

Elongation of rod = 0.19732 mm

(b) Poisson ratio = lateral strain / longitudinal strain

0.3 = lateral strain / 0.0009866

Lateral strain = 0.000296

Lateral strain = Change in diameter / original diameter

0.000296 = Change in diameter / 22

Change in diameter = 0.00651 mm

3 0

3 years ago

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