Answer:
the amount of heat of energy released or absorbed by a substance.
Explanation:
Mathematically, latent heat of fusion is given by the formula;
Q = mL
Where;
Q is the quantity of heat energy measured in Joules.
m is the mass measured in kilograms.
L is the specific heat latent heat of fusion.
In the formulas for latent heat of fusion and latent heat of vaporization, Q represents the amount of heat of energy released or absorbed by a substance.
In the process of heat conduction, thermal energy is usually transferred from fast moving particles to slow moving particles during the collision of these particles. Also, thermal energy is typically transferred between objects that has different degrees of temperature and materials (particles) that are directly in contact with each other but differ in their ability to accept or give up electrons.
The solution for this is:
Power = Energy transferred / Time taken
Energy Transferred in one second ( Power) = mgh/s
= (1.2x10^6)(9.8)(50) = 588000000 J/s
Power = 588000000 W
Or
Power is work done / time
Work done in one second = [ rate of fall of mass]
gh = 1.2* *9.81*50 x 10^6 J/s
= 5.886e+8 W
Answer:
115 m/s, 414 km/hr
Explanation:
There are two forces acting on a skydiver: gravity and air resistance (drag). At terminal velocity, the two forces are equal and opposite.
∑F = ma
D − mg = 0
D = mg
Drag force is defined as:
D = ½ ρ v² C A
where ρ is the fluid density,
v is the velocity,
C is the drag coefficient,
and A is the cross sectional surface area.
Substituting and solving for v:
½ ρ v² C A = mg
v² = 2mg / (ρCA)
v = √(2mg / (ρCA))
We're given values for m and A, and we know the value of g. We need to look up ρ and C.
Density of air depends on pressure and temperature (which vary with elevation), but we can estimate ρ ≈ 1.21 kg/m³.
For a skydiver falling headfirst, C ≈ 0.7.
Substituting all values:
v = √(2 × 80.0 kg × 9.8 m/s² / (1.21 kg/m³ × 0.7 × 0.140 m²))
v = 115 m/s
v = 115 m/s × (1 km / 1000 m) × (3600 s / hr)
v = 414 km/hr
Answer:
Explanation:
We shall apply conservation of momentum along x and y axis.
Let the final momentum of second particle be p₁ along x axis and p₂ along y axis.
Considering momentum along x axis
2 + 0 = 3 cos 45 + p₁
p₁ = 2-2.12 = - 0.12 kg m/s
Considering momentum along y axis
4 + 0 = 3 sin 45 + p₂
p₂ = 4-2.12 = 1.88 kg m/s
Final momentum = √ ( p₁² + p₂² )
=√ ( .12² + 1.88² )
= 1.88 approx
A) position time graph for both is shown
here one of the graph is of lesser slope which means it is moving with less speed while other have larger slope which shows larger speed
At one point they intersects which is the point where they both will meet
B) Let the two will meet after time "t"
now we can say that
if they both will meet after time "t"
then the total distance moved by you and other person will be same as the distance between you and home
so it is given as
so they will meet after t = 6 min
so from position time graph we can see that two will meet after t = 6 min where at this position two graphs will intersect
