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Arlecino [84]
2 years ago
9

The complete factorization of -12x^3 + 14x^2 +6x is -2x(ax + 1)(2x-3). What is the value of a?

Mathematics
1 answer:
tester [92]2 years ago
4 0

Answer:

a = 3

Step-by-step explanation:

-12x³+14x²+6x = -2x(ax+1)(2x-3)

<em>Divide both sides by -2x(2x-3)</em>

\frac{-2x(ax+1)(2x-3)}{-2x(2x-3)} = - \frac{12x^{3} }{-2x(2x-3)} + \frac{14x^{2} }{-2x(2x-3)} +\frac{6x}{-2x(2x-3)}

ax+1=3x+1

<em>Subtract 1 from both sides</em>

ax=3x

<em>Divide both sides by x</em>

a=3

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