Question

The complete factorization of -12x^3 + 14x^2 +6x is -2x(ax + 1)(2x-3). What is the value of a?

Answer 1

Answer:

a = 3

Step-by-step explanation:

-12x³+14x²+6x = -2x(ax+1)(2x-3)

Divide both sides by -2x(2x-3)

$\frac{-2x(ax+1)(2x-3)}{-2x(2x-3)} = - \frac{12x^{3} }{-2x(2x-3)} + \frac{14x^{2} }{-2x(2x-3)} +\frac{6x}{-2x(2x-3)}$

ax+1=3x+1

Subtract 1 from both sides

ax=3x

Divide both sides by x

a=3