Question

An engineer is undertaking some reconnaissance by pacing on a construction site. The engineer takes 26 steps per 20m, the ground he is walking on has a vertical slope angle of 6. The engineer takes 152 steps. How far has he travelled horizontally (in metres)?(only enter numeric answer to 2 decimal places, no alpha characters)

Answer 1

Answer:

Thus the distance traveled horizontally is 116.28 m

Solution:

As per the question:

Distance covered in 26 steps = 20 m

Thus

Distance covered in one step, step size = $\frac{20}{26}$

Total steps taken = 152

Now, the distance covered in 152 steps = $one step size\times 152$

The distance covered in 152 steps, D = $\frac{20}{26}\times 152 = 116.92 m$

The above distances are on a slope of $6^{\circ}$ above horizontal.

Thus the horizontal component of this distance is given by:

$d_{H} = Dcos6^{\circ}$

where

$d_{H}$ = horizontal component of distance, D

$d_{H} = 116.92cos6^{\circ} = 116.28 m$