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larisa86 [58]
4 years ago
8

Summarize Newton’s First Law

Physics
1 answer:
Tamiku [17]4 years ago
8 0
Newton's first law is "An object at rest stays at rest and an object in motion stays in motion with the same speed and in the same direction unless acted upon by an unbalanced force."

Basically it means an object won't move unless something moves it, and an object won't stop moving unless something stops it.
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ametal of mass 0.6kg is heated by an electric heater connected to 15v batter when the ammeter reading is 3A its tempeeature rise
Vedmedyk [2.9K]

Answer:

692 J/kg/°C

Explanation:

Electric energy added = amount of heat

Power × time = mass × SHC × increase in temperature

Pt = mCΔT

(15 V × 3 A) (10 min × 60 s/min) = (0.6 kg) C (85°C − 20°C)

C = 692 J/kg/°C

6 0
3 years ago
A particular automotive wheel has an angular moment of inertia of 12 kg*m^2, and is decelerated from 135 rpm to 0 rpm in 8 secon
lozanna [386]

Answer:

(A) Torque required is 21.205 N-m

(b) Wok done will be equal to 1199.1286 j

Explanation:

We have given moment of inertia I=12kgm^2

Wheel deaccelerate from 135 rpm to 0 rpm

135 rpm = 135\times \frac{2\pi }{60}=14.1371rad/sec

Time t = 8 sec

So angular speed \omega _i=135rpm and \omega _f=0rpm

Angular acceleration is given by \alpha =\frac{\omega _f-\omega _i}{t}=\frac{0-14.1371}{8}=--1.7671rad/sec^2

Torque is given by torque \tau =I\alpha

=12\times 1.7671=21.205N-m

Work done to accelerate the vehicle is

\Delta w=K_I-K_F

\Delta W=\frac{1}{2}\times 12\times 14.137^2-\frac{1}{2}\times 12\times0^2=1199.1286J

8 0
4 years ago
Betty weighs 400 N and she is sitting on a playground swing seat that hangs 0.21 m above the ground. Tom pulls the swing back an
disa [49]

Answer:

4.15 m/s

Explanation:

As the total energy must be conserved (neglecting air resistance) the change in gravitational potential energy, must be equal to the change in kinetic energy:

ΔE = ΔK + ΔU =0

If we take as a zero reference level for the gravitational potential energy, the height of the swing seat above the ground, (which is equal to 0.21 m), we can find the initial gravitational energy, considering the height of the point where the seat is released, regarding this point:

h₀ = 1.09 m -0.21 m = 0.88 m

⇒ U₀ = m*g*h₀ = 400 N*0.88 m = 352 J

As Uf = 0, ΔU = Uf -U₀ = -352 J

As the swing starts from rest, K₀=0, so we can say:

ΔK = Kf = \frac{1}{2} *m*vf^{2}  (1)

As ΔK = -ΔU ⇒ ΔK = 352 J (2)

From (1) and (2) we can solve for vf, as follows:

vf = \sqrt{\frac{2*352J}{40.8kg}} = 4.15 m/s

So, when the swing passes through its lowest position, Betty moves at 4.15 m/s.

5 0
4 years ago
Can someone help me on this please?
vladimir2022 [97]
The brown hair for sure :)
7 0
3 years ago
The graph shows how the vertical velocity of a parachutist changes from the moment the parachutist jumps from the aircraft until
soldi70 [24.7K]

Answer:

BUT WHY

Explanation:

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4 years ago
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