Answer:
The probability of selecting randomly 6 packets such that the first 4 contain cocaine and 2 not is 0.3522.
Step-by-step explanation:
Probabilities of selecting 4 packets with the ilegal substance:
= 
Combinassions possible= 1365
Probabilities of selecting 2 packets with white powder:
= 
Combinations possible= 10
Probabilities of selecting 6 packets from the totality of them:
= 
Combinations possible= 38760
The probability of picking 4 with the substance and 2 with only white powder is:
= 0.3522
I hope this answer helps you.
Answer:
the answer is C
Step-by-step explanation:
![\sqrt[3]{ {n}^{3} } = \sqrt[3]{380}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B%20%7Bn%7D%5E%7B3%7D%20%7D%20%20%3D%20%20%5Csqrt%5B3%5D%7B380%7D%20)
n = 7.25
7 < 7.25 <8
Answer:
More clarification
Step-by-step explanation:
2 of a white ball =2/30 =1/15;
This is the probability of picking a black ball.
Let the number of black ball be X
x/(x +20)= 1/15[ probability of picking black ball ]
15x = x + 20 ; by cross multiplication
14x=20; x = 20/ 14 =1.42 = 1 [ approximately]
But to satisfy the premise given above; we have to approximate the no of balls to 2
The numeric value of the b is 0.23 which satisfy the given equation.
According to the statement
We have to find that the value of the b.
So, For this purpose, we know that the
The numeric value refers to the worth of each digit depending on where it lies in the number.
From the given information:
The equation is a
3(2b + 3)² = 36
then to find the value of b rearrange the terms then
(2b + 3)² = 12
(2b + 3) = \sqrt{12}
(2b) = \sqrt{12} -3
then
b = \sqrt{12} -3/ 2
b = 3.46 - 3/2
b = 0.46/2
b = 0.23.
So, The numeric value of the b is 0.23 which satisfy the given equation.
Learn more about numeric value here
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(700x6x20)/100 put this on the calculator to get the answer sorry I don’t have one now
