Using a coordinate geometry approach, identify the coordinates of the vertex of the angle and the equations of the lines forming the two sides; choose an arbitrary point on each line and find the general equation of the line connecting them (the third side of your triangle); write the equation of the line that meets the conditions of angle bisection (that it is equidistant from each of the lines forming the two sides); solve simultaneously the equations for this line and for the third side.
If you are trying to do this as an absolute proof for any angle and triangle, your equations will be full of unknowns (x1, y1, m1, etc), and will need a lot of careful algebraic manipulation. If you have a specific triangle in mind, the presence of numbers makes the solution of the equations much simpler.
Of course, this is not the only method of proof available, but it is the simplest to describe as a general procedure without actually writing out the required proof!
<span>More intuitively, since the angle bisector must be midway between the two rays that form the adjacent sides of the triangle, it must cross any line which intersects those two rays, which the third side of the triangle must do. This is very hard to show as a proof without using diagrams.</span>
Answer:
d)2 1/2
Step-by-step explanation:
Try <span>38.465cm I'm not good at math but its the best I could do
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Givn : OK = 3, OJ = 30, KN = 1, JM = 3
ON=OK+KN=3+1=4
OM=OJ+JM=30+10=40
In triangles OKJ & ONM,
OKOJ=330=110
ONOM=440=110
Angle O is common in both the triangles.
Two sides are in same proportion and the included angle is common (SAS) . Hence both the triangles are similar.
That means KJNM=110 or the two sides are parallel.
Hence ˆK=ˆN,ˆJ=ˆM corresponding angles.
The longest work is 2 times the shortest worm.
