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Amiraneli [1.4K]
2 years ago
9

Select the correct answer

Mathematics
1 answer:
solong [7]2 years ago
3 0

Answer: OPTION C.

Step-by-step explanation:

Given the functions:

f(x)=2x^2-x-6\\\\g(x)=x^2-4

We need to divide f(x) by g(x) in order to find f(x)÷g(x). Then:

f(x)÷g(x)=\frac{2x^2-x-6}{x^2-4}

Factorizing and simplifying, we get:

f(x)÷g(x)=\frac{(2x+3)(x-2)}{(x+2)(x-2)}

f(x)÷g(x)=\frac{2x+3}{x+2} 

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The sets of numbers 3, 4, 5 and 8, 15, 17 are Pythagorean triples. Use what you know about the Pythagorean Theorem and explain o
konstantin123 [22]

Answer:

When we have 3 numbers, like:

a, b and c.

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a < b < c.

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Now that we know this, we can check if the given sets are Pythagorean triples.

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3^2 + 4^2 = 5^2

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3^2 + 4^2 = 9 + 16 = 25

and the right side:

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2) 8, 15, 17

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4 0
2 years ago
Which Two Numbers Add Up To Negative 26 And Multiply To 11?
Fynjy0 [20]
Xy=11
x+y=-26


x+y=-26
minus x both sides
y=-26-x

sub for y
x(-26-x)=11
-26x-x^2=11
add 26x+x^2 both sides
x^2+26x+11=0

ax^2+bx+c=0
x=\frac{-b+/- \sqrt{b^{2}-4ac} }{2a}


a=1
b=26
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x=\frac{-26+/-\sqrt{26^{2}-4(1)(11)} }{2(1)}
x=\frac{-26+/-\sqrt{676-44} }{2}
x=\frac{-26+/-\sqrt{632} }{2}
x=\frac{-26+/-2\sqrt{158} }{2}
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x=-13+\sqrt{158} or -13-\sqrt{158}

aprox

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those are the numbers
5 0
3 years ago
PLEASE HELP, and dont forget to show work!
weeeeeb [17]
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