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Archy [21]
3 years ago
11

A medical equipment industry manufactures X-ray machines. The unit cost (the cost in dollars to make each X-ray machine) depends

on the number of machines made. If machines are made, then the unit cost is given by the function . What is the minimum unit cost?Do not round your answer.
Mathematics
1 answer:
lyudmila [28]3 years ago
8 0

Answer:

$14,362

Step-by-step explanation:

The computation of the minimum unit cost is shown below:

Given that

0.6x^2 - 108x + 19,222

And as we know that the quadratic equation form is

ax^2 + bx + c

where

a = 0.6

b = -108

c = 19,222

Now for determining the minimal cost we applied the following formula which is

= \frac{-b}{2a} \\\\ =  \frac{-(-108)}{2\times 0.6} \\\\ =  \frac{108}{1.2}

= 90

Now put these values to the above equation

= 0.6\times 90^{2} - 108 \times 90 + 19,222

= 14,362

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Square A is a scaled version of square B. The dimensions of square A are three times the dimensions of square B. The area of squ
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Answer:

The side of square A is 30 cm.

Step-by-step explanation:

Given that,

The dimensions of square A are three times the dimensions of square B.

The area of square A is 900 sq cm.

Side of square A = 3( side of square B)

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Side of square A, a = 3b

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3 years ago
Use Lagrange multipliers to find the dimensions of the box with volume 1728 cm3 that has minimal surface area. (Enter the dimens
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Answer:

(x,y,z) = (12,12,12) cm

Step-by-step explanation:

The box is assumed to be a closed box.

The surface area of a box of dimension x, y and z is given by

S = 2xy + 2xz + 2yz

We're to minimize this function subject to the constraint that

xyz = 1728

The constraint can be rewritten as

xyz - 1728 = 0

Using Lagrange multiplier, we then write the equation in Lagrange form

Lagrange function = Function - λ(constraint)

where λ = Lagrange factor, which can be a function of x, y and z

L(x,y,z) = 2xy + 2xz + 2yz - λ(xyz - 1728)

We then take the partial derivatives of the Lagrange function with respect to x, y, z and λ. Because these are turning points, each of the partial derivatives is equal to 0.

(∂L/∂x) = 2y + 2z - λyz = 0

λ = (2y + 2z)/yz = (2/z) + (2/y)

(∂L/∂y) = 2x + 2z - λxz = 0

λ = (2x + 2z)/xz = (2/z) + (2/x)

(∂L/∂z) = 2x + 2y - λxy = 0

λ = (2x + 2y)/xy = (2/y) + (2/x)

(∂L/∂λ) = xyz - 1728 = 0

We can then equate the values of λ from the first 3 partial derivatives and solve for the values of x, y and z

(2/z) + (2/y) = (2/z) + (2/x)

(2/y) = (2/x)

y = x

Also,

(2/z) + (2/x) = (2/y) + (2/x)

(2/z) = (2/y)

z = y

Hence, at the point where the box has minimal area,

x = y = z

Putting these into the constraint equation or the solution of the fourth partial derivative,

xyz - 1728 = 0

x³ = 1728

x = 12 cm

x = y = z = 12 cm.

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