Ask question

Ask question

All categories

3 years ago

9

What is the weight of a glider with a mass of 5.7 grams? Hint: watch your units!

1 answer:

ohaa [14]3 years ago

4 0

Answer:0.0057

Step-by-step explanation:

You might be interested in

Zoey has 99 years .She plans to make 5 bangles .Each bangle is made using 30 beads how many more beads does zoey need?

drek231 [11]

Note: I am assuming you meant to say:

Zoey has 99 beads instead of 99 years.

Answer:

Zoey needs 51 more beads to make 5 bangles.

Step-by-step explanation:

Total number of beads Zoey currently has = 99 beads

Beads need to make one bangel = 30 beads

so

Beads need to make 5 bangles = 30 × 5 = 150 beads

Since she has already 99 beads.

So, all we need s to subtract 99 beads from 150 beads.

Therefore,

The number of beads Zoey needs = 150 - 99

= 51 beads

Thus, Zoey needs 51 more beads to make 5 bangles.

4 0

3 years ago

M-2<-8 or m/8>1<br>I don't know how to solve this

Shkiper50 [21]

I hope this helps you

5 0

3 years ago

Please answer this correctly without making mistakes I want ace expert and genius people to answer this correctly without making

soldi70 [24.7K]

Answer:

yz + z = -22

Step-by-step explanation:

Ok so you are already the number that y = 10 and z = -2. You will plug these number in the equation in order to find the answer. :-

y = 10 and z = -2

yz + z

<u>10(-2)</u> - 2

<u>-20 - 2</u>

-22

Hope this helps, thank you :) !!

6 0

3 years ago

Trapezoids and kites

lisov135 [29]

QUESTION 3

The sum of the interior angles of a kite is $360\degree$ .

$\Rightarrow 36\degree +70\degree+m$ .

$\Rightarrow 106\degree+m$ .

$\Rightarrow m$ .

$\Rightarrow m$ .

But the two remaining opposite angles of the kite are congruent.

$\Rightarrow m$

$\Rightarrow m$ .

$\Rightarrow 2m$ .

$\Rightarrow m$ .

$\Rightarrow m$ .

QUESTION 4

RH is the hypotenuse of the right triangle formed by the triangle with side lengths, RH,12, and 20.

Using the Pythagoras Theorem, we obtain;

$|RH|^2=12^2+20^2$

$|RH|^2=144+400$

$|RH|^2=544$

$|RH|=\sqrt{544}$

$|RH|=4\sqrt{34}$

QUESTION 5

The given figure is an isosceles trapezium.

The base angles of an isosceles trapezium are equal.

Therefore $m$

QUESTION 6

The measure of angle Y and Z are supplementary angles.

The two angles form a pair of co-interior angles of the trapezium.

This implies that;

$m$

$\Rightarrow m$

$\Rightarrow m$

QUESTION 7

The sum of the interior angles of a kite is $360\degree$ .

$\Rightarrow 48\degree +110\degree+m$ .

$\Rightarrow 158\degree+m$ .

$\Rightarrow m$ .

$\Rightarrow m$ .

But the two remaining opposite angles are congruent.

$\Rightarrow m$

$\Rightarrow m$ .

$\Rightarrow 2m$ .

$\Rightarrow m$ .

$\Rightarrow m$ .

QUESTION 8

The diagonals of the kite meet at right angles.

The length of BC can also be found using Pythagoras Theorem;

$|BC|^2=4^2+7^2$

$\Rightarrow |BC|^2=16+49$

$\Rightarrow |BC|^2=65$

$\Rightarrow |BC|=\sqrt{65}$

QUESTION 9.

The sum of the interior angles of a trapezium is $360\degree$ .

$\Rightarrow m$ .

$\Rightarrow m$ .

But the measure of angle M and K are congruent.

$\Rightarrow m$ .

$\Rightarrow m$ .

$\Rightarrow m$ .

$\Rightarrow m$ .

6 0

3 years ago

if you’re good with set theory in math 30 please help with questions 31 and 32!! real answers only !!

GREYUIT [131]

Answer: 31) d 32) c

<u>Step-by-step explanation:</u>

31)

A = {1, 3, 5, 15}

B = {2, 3, 5, 7}

A ∪ B = {1, 2, 3, 5, 7, 15}

C = {2, 4, 6, 8}

(A ∪ B) ∩ C = {1, 2, 3, 5, 7, 15} ∩ {2, 4, 6, 8} = {2}

<em>2 is the only number in both sets</em>

32)

The pattern is: reflection, add symbol, ..., reflection, add symbol.

The last image shown is: add symbol

So the next image will be: reflection (flipped to the left)

7 0

3 years ago