Solve |2x - 5| = 4 someone help

1 answer:

4 0

$\text{Solve the absolute value, remember, there are two answers/outcomes}\\\\\text{First outcome:}\\\\2x - 5 = 4\\\\\text{Solve:}\\\\2x - 5 = 4\\\\\text{Add 5 to both sides}\\\\2x=9\\\\\text{Divide by 2}\\\\\boxed{x=\frac{9}{2}}\\\\\text{Second outcome:}\\\\2x - 5 = -4\\\\\text{Add 5 to both sides}\\\\2x=1\\\\\text{Divide by 2}\\\\\boxed{x=\frac{1}{2}}$

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If the factors of function f are (x - 6) and (x - 1), what are the zeros of function f?

lidiya [134]

X=6 and x=1

You can find your zeros by determining what you have to plug into the function in order for it to equal zero

If we plug in 6, for example we’d get (6-6)(x-1)

Simplified this is 0(x-1)

Anything times 0 is 0, so this is one of our zeros.

Same goes for x-1, we just need to plug in 1 for it to equal 0

Therefore there are zeros at x=1 and x=6 :))

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jok3333 [9.3K]

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Read 2 more answers

Find the length of side x in simplest radical form with a rational denominator.

Leto [7]

<h3>Answer: $2\sqrt{5}$ </h3>

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Explanation:

Both legs are the same length, as indicated by the tickmark.

a = $\sqrt{10}$
b = $\sqrt{10}$
c = x

Use the pythagorean theorem to solve for x

$a^2+b^2 = c^2\\\\( \sqrt{10} )^2 + ( \sqrt{10} )^2 = x^2\\\\10 + 10 = x^2\\\\x^2 = 20\\\\x = \sqrt{20}\\\\x = \sqrt{4*5}\\\\x = \sqrt{4}*\sqrt{5}\\\\x = 2\sqrt{5}\\\\$