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goblinko [34]
3 years ago
5

Pine Valley Furniture wants to use Internet systems to provide value to its customers and staff. There are many software technol

ogies available to internet systems development teams, including SOAP, HTML, JSON, XML, CSS, ASP.NET, Objective C, php, JAVA™, Python, Ruby, AJAX, Swift™, AngularJS, Bootstrap, jQuery, R, and many more.
Choose an option below to complete this assignment:Write a 4-page paper that compares and contrasts at least three Internet systems development software technologies.Explain why an Internet systems developer might choose one technology over another technology.Explain how these technologies can bring value to the business or organization.Incorporate additional research or academic information to support your paper.
Engineering
1 answer:
qaws [65]3 years ago
3 0

Answer:

In these present generation, every day a new technology is coming. People are adopting these technologies very fast. If we think ," we have learned C language , now why to worry about java " . Then that is called you are bounding yourself to a technology. You are not ready for the growth.

With the invent of new technologies, if we have basic idea of how it works, we can simply implement it. At the end of day , it doesn't really matter how many lines of code you have written , it is just about efficiency. How Efficiently you are writing your code.

So, When Efficiency is the only thing that matters to the organizations , they are ready to take up new technologies and they will try to work-out with them. This is the trend in IT .Every month a new technology comes, respective people will be trained on that and they will implement/migrate the existing projects into new efficient model.

If we really learn and implement things using advance technologies , people will get an exposure to new technologies as well as the organization will get good impact on them , for spending resources on learning new technologies in the market. Apart from that , everyone will be happy for adopting new stack of technologies for them.

If we observe the existing technologies:

Programming languages are :

C, JAVA, PYTHON,R , SCALA

web development technologies:

HTML,CSS , JAVASCRIPT, ANGULAR,REACT , BOOTSTRAP , NODE.JS, MongoDB....etc

databases skills:

SQL, oracle,mySQL, postgres and so many cloud databases also available.

So, there are plenty of opportunities that are available . There are life time courses available to learn new technologies.

LEARN..RELEARN....UNLEARN

this is the motto of many organizations. They simply learn one technology and they'll forget it . If something new comes, they'll learn and implements it.This is the current trend in software industry.

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Why do giant stars become planetary nebulas while supergiant stars become supernovas when their nuclear fusion slows and is over
sashaice [31]

The reason why giant stars become planetary nebulas is  Supergiant stars do not have enough mass to generate the gravity necessary to cause a planetary nebula.

<h3>Why do giant stars become planetary nebulae?</h3>

A planetary nebula is known to be formed or created by a dying star. A red giant is known to be unstable and thus emit pulses of gas that is said to form a sphere around the dying star and thus they are said to  be ionized by the ultraviolet radiation that the star is known to releases.

Learn more about  giant stars from

brainly.com/question/27111741

#SPJ1

3 0
2 years ago
1. A soil core sampling tube of 4 cm diameter, 12 cm length and initial mass of 0.525 kg (sample only), was dried at 105o C and
belka [17]

Answer:

porosity = 0.07 or 7%

dry bulk density = 3.25g/cm3]

water content =

Explanation:

bulk density = dry Mass / volume of  sample

dry mass = 0.490kg = 490g

volume = πr2h = 3.142 * 2 *2 *12 = 150.8cm3

density = 490/150.8 = 3.25g/cm3

porosity = \frac{wet mass - dry mass }{wet mass} = \frac{0.525 - 0.49}{0.525} = 0.07 or 7%

water content =  \frac{wet mass - dry mass}{wet mass} = 7%

8 0
3 years ago
Read 2 more answers
A smooth sphere with a diameter of 6 inches and a density of 493 lbm/ft^3 falls at terminal speed through sea water (S.G.=1.0027
Pachacha [2.7K]

Given:

diameter of sphere, d = 6 inches

radius of sphere, r = \frac{d}{2} = 3 inches

density,  \rho} = 493 lbm/ ft^{3}

S.G = 1.0027

g = 9.8 m/ m^{2} = 386.22 inch/ s^{2}

Solution:

Using the formula for terminal velocity,

v_{T} = \sqrt{\frac{2V\rho  g}{A \rho C_{d}}}              (1)

(Since, m = V\times \rho)

where,

V = volume of sphere

C_{d} = drag coefficient

Now,

Surface area of sphere, A = 4\pi r^{2}

Volume of sphere, V = \frac{4}{3} \pi r^{3}

Using the above formulae in eqn (1):

v_{T} = \sqrt{\frac{2\times \frac{4}{3} \pir^{3}\rho  g}{4\pi r^{2} \rho C_{d}}}

v_{T} = \sqrt{\frac{2gr}{3C_{d}}}  

v_{T} = \sqrt{\frac{2\times 386.22\times 3}{3C_{d}}}

Therefore, terminal velcity is given by:

v_{T} = \frac{27.79}{\sqrt{C_d}} inch/sec

3 0
3 years ago
Compute the theoretical density of ZnS given that the Zn-S distance and bond angle are 0.234 nm and 109.5o, respectively. The at
andriy [413]

Answer: the theoretical density is 4.1109 g/cm³

Explanation:  

first the image of one set of ZnS bonding in the crystal structure, we calculate the value of angle θ

θ + ∅ + 90° = 180°

θ = 90° - ∅

θ = 90° - ( 109.5° / 2 )

θ = 35.25°

next we calculate the value of x from the geometry

given that;  distance angle d = 0.234

x = dsinθ

= 0.234 × sin35.25°)

= 0.135 nm = 0.135 × 10⁻⁷ cm

next we calculate the length of the unit cell

a = 4x

a = 4(0.135)

a = 0.54 nm = 0.54 × 10⁻⁷ cm

next we calculate number of formula units

n' = (no of corner atoms in unit ell × contribution of each corner atom in unit cell) + ( no of face center atom in a unit cell × contribution of each face center atom in a unit cell)

n' = 8 × 1/8) + ( 6 × 1/2)

= 1 + 3

= 4

next we calculate the theoretical density using  this equation

P = [n'∑(Ac + AA)] / [Vc.NA]

= [n'∑(Ac + AA)] / [(a)³NA]

where the ∑Ac is sum of atomic weights of all cations in the formula unit( 65.41 g/mol)

∑AA is the sum of weights of all anions in the formula unit( 32.06 g/mol)

Na is the Avogadro’s number( 6.023 × 10²³ units/mole)

so we substitute

P = [4( 65.41 + 32.06)] / [ ( 0.54 × 10⁻⁷ )³ × (6.023 × 10²³)]

= 389.88 / 94.84

= 4.1109 g/cm³

therefore the theoretical density is 4.1109 g/cm³

5 0
2 years ago
Determine the deflection at the center of the beam. Express your answer in terms of some or all of the variables LLL, EEE, III,
Rom4ik [11]

Answer:

See explanations for step by step procedures to get answer.

Explanation:

Given that;

Determine the deflection at the center of the beam. Express your answer in terms of some or all of the variables LLL, EEE, III, and M0M0M_0. Enter positive value if the deflection is upward and negative value if the deflection is downward.

4 0
3 years ago
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