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goblinko [34]
3 years ago
5

Pine Valley Furniture wants to use Internet systems to provide value to its customers and staff. There are many software technol

ogies available to internet systems development teams, including SOAP, HTML, JSON, XML, CSS, ASP.NET, Objective C, php, JAVA™, Python, Ruby, AJAX, Swift™, AngularJS, Bootstrap, jQuery, R, and many more.
Choose an option below to complete this assignment:Write a 4-page paper that compares and contrasts at least three Internet systems development software technologies.Explain why an Internet systems developer might choose one technology over another technology.Explain how these technologies can bring value to the business or organization.Incorporate additional research or academic information to support your paper.
Engineering
1 answer:
qaws [65]3 years ago
3 0

Answer:

In these present generation, every day a new technology is coming. People are adopting these technologies very fast. If we think ," we have learned C language , now why to worry about java " . Then that is called you are bounding yourself to a technology. You are not ready for the growth.

With the invent of new technologies, if we have basic idea of how it works, we can simply implement it. At the end of day , it doesn't really matter how many lines of code you have written , it is just about efficiency. How Efficiently you are writing your code.

So, When Efficiency is the only thing that matters to the organizations , they are ready to take up new technologies and they will try to work-out with them. This is the trend in IT .Every month a new technology comes, respective people will be trained on that and they will implement/migrate the existing projects into new efficient model.

If we really learn and implement things using advance technologies , people will get an exposure to new technologies as well as the organization will get good impact on them , for spending resources on learning new technologies in the market. Apart from that , everyone will be happy for adopting new stack of technologies for them.

If we observe the existing technologies:

Programming languages are :

C, JAVA, PYTHON,R , SCALA

web development technologies:

HTML,CSS , JAVASCRIPT, ANGULAR,REACT , BOOTSTRAP , NODE.JS, MongoDB....etc

databases skills:

SQL, oracle,mySQL, postgres and so many cloud databases also available.

So, there are plenty of opportunities that are available . There are life time courses available to learn new technologies.

LEARN..RELEARN....UNLEARN

this is the motto of many organizations. They simply learn one technology and they'll forget it . If something new comes, they'll learn and implements it.This is the current trend in software industry.

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The cable outside diameter and the conduit inside diameter.
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The complexity of bfs and dfs
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BFS uses Queue to find the shortest path. DFS uses Stack to find the shortest path. ... Time Complexity of BFS = O(V+E) where V is vertices and E is edges. Time Complexity of DFS is also O(V+E) where V is vertices and E is edges.

Explanation:

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2 years ago
Calculate the number of vacancies per cubic meter for some metal, M, at 783°C. The energy for vacancy formation is 0.95 eV/atom,
djyliett [7]

Answer:

Following are the solution to this question:

Explanation:

The number of vacancies by the cubic meter is determined.  

N_V =N exp(\frac{Q_v}{kT})

      = \frac{N_A \rho}{A} exp (\frac{Q_v}{kT})

      =  \frac{6.022 \times 10^{23} \times 6.10}{43.41} \exp(\frac{-0.95}{8.62\times 10^{-5} \times (783+273)})\\\\=  \frac{36.7342 \times 10^{23}}{43.41} \exp(\frac{-0.95}{0.0313626})\\\\=  0.846215158 \times 10^{23} \exp(-30.290856)\\\\

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7 0
3 years ago
An aircraft component is fabricated from an aluminum alloy that has a plane strain fracture toughness of 30 . It has been determ
UNO [17]

Answer:

fracture will occur since ( 31.8 Mpa√m ) is greater than the K_{Ic of the material ( 30 Mpa√m )

Explanation:

Given the data in the question;

To determine whether the aircraft component will fracture, given a fracture toughness of 30 Mpa√m, stress level of 355 and maximum internal crack length of 1.39 mm.

On a similar component, it has been said that fracture results at a stress of 237 MPa when the maximum (or critical) internal crack length is 2.78 mm.

so we first of all solve for the parameter Y in the condition where fracture occurred.

K_{Ic = 30 Mpa√m

σ = 237 MPa

2α = 2.78 mm = 2.78 × 10⁻³ m  

so

Y = K_{Ic / σ√πα

we substitute

Y = (30 Mpa√m) / (237 MPa)√(π(2.78 × 10⁻³ m / 2 ) )

Y =  (30 Mpa) / (237)( 0.06608187 )

Y = 30 / 15.6614

Y = 1.9155

Next we solve for Yσ√πα for the second case;

σ = 355 Mpa, 2α = 1.39 mm = 1.39 × 10⁻³ m

so

Yσ√πα = 1.9155 × 355 Mpa × √( π × (1.39 × 10⁻³ m / 2) )

= 1.9155 × 355 × 0.0467269

= 31.8 Mpa√m

so

( 31.8 Mpa√m ) > K_{Ic ( 30 Mpa√m )

Therefore, fracture will occur since ( 31.8 Mpa√m ) is greater than the K_{Ic of the material ( 30 Mpa√m )

4 0
2 years ago
One cylinder in the diesel engine of a truck has an initial volume of 650 cm3 . Air is admitted to the cylinder at 35 ∘C and a p
kupik [55]

Answer:

1) the final temperature is T2 = 876.76°C

2) the final volume is V2 = 24.14 cm³

Explanation:

We can model the gas behaviour as an ideal gas, then

P*V=n*R*T

since the gas is rapidly compressed and the thermal conductivity of a gas is low a we can assume that there is an insignificant heat transfer in that time, therefore for adiabatic conditions:

P*V^k = constant = C, k= adiabatic coefficient for air = 1.4

then the work will be

W = ∫ P dV = ∫ C*V^(-k) dV = C*[((V2^(-k+1)-V1^(-k+1)]/( -k +1) = (P2*V2 - P1*V1)/(1-k)= nR(T2-T1)/(1-k) = (P1*V1/T1)*(T2-T1)/(1-k)

W = (P1*V1/T1)*(T2-T1)/(1-k)  

T2 = (1-k)W* T1/(P1*V1) +T1

replacing values (W=-450 J since it is the work done by the gas to the piston)

T2 = (1-1.4)*(-450J) *308K/(101325 Pa*650*10^-6 m³) + 308 K= 1149.76 K = 876.76°C

the final volume is

TV^(k-1)= constant

therefore

T2/T1= (V2/V1)^(1-k)

V2 = V1* (T2/T1)^(1/(1-k)) = 650 cm³ * (1149.76K/308K)^(1/(1-1.4)) = 24.14 cm³

3 0
3 years ago
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