Some friends plotted the locations of their house on a map. brianna's house is at (1,6), Jordan's house is at (5,3). What is one
possible path from brianna's house to jordan's house?
1 answer:
Let
A (1,6)------> location <span>brianna's house on a map
B </span>(5,3)------> location Jordan's house on a map
we know that
One possible path from brianna's house to jordan's house it's a straight line ( <span>the shortest distance)</span>
using a graph tool
see the attached figure
find the distance points AB
d=√[(y2-y1)²+(x2-x1)²]-----> d=√[(3-6)²+(5-1)²]----> d=√[3²+4²]
d=√25----> d=25 units
the distance from brianna's house to jordan's house is 25 units
A (1,6)------> location <span>brianna's house on a map
B </span>(5,3)------> location Jordan's house on a map
we know that
One possible path from brianna's house to jordan's house it's a straight line ( <span>the shortest distance)</span>
using a graph tool
see the attached figure
find the distance points AB
d=√[(y2-y1)²+(x2-x1)²]-----> d=√[(3-6)²+(5-1)²]----> d=√[3²+4²]
d=√25----> d=25 units
the distance from brianna's house to jordan's house is 25 units
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Answer:
Step-by-step explanation:
Given
Required
Determine the image P'
P' is calculated by multiplying P and k.
i.e.
This gives:
<em>Hence, the image P' after dilating P is (-10,-8)</em>