Answer:
1.7 m
Explanation:
= Velocity of ball in x direction = 4.47 m/s
= Velocity of ball in y direction = 0
g = Acceleration due to gravity = 
t = Time taken
= Vertical displacement = 0.7 m

Horizontal displacement is given by

The passenger should throw the ball 1.7 m in front of the bucket.
Answer:
1.) Covering the ceiling and walls with soft perforated boards
2.) Hanging curtains round the hall
3.) Having more opening in the wall.
Explanation:
This is due to what we called Reverberation due to poor acoustic properties.
Reverberation can be reduced by;
1.) Covering the ceiling and walls with soft perforated boards
2.) Hanging curtains round the hall
3.) Having more opening in the wall.
Answer:
w = 0.189 rad/ s
Explanation:
This exercise we work with the conservation of the moment, the system is made up of the merry-go-round and the child, for which we write the moment of two instants
Initial
L₀ = I₀ w₀
Final
= I w
L₀ = L_{f}
I₀ w₀ = I_{f} w
.w = I₀/I_{f} w₀
The initial moment of inertia is
I₀ = 500 kg. m2
The final moment of inertia
= 500 + m r²
I_{f} = 500 + 20 1.5
I_{f} = 530 kg m²
Initial angular velocity
w₀ = 0.20 rad / s
Let's calculate
w = 500/530 0.20
w = 0.189 rad / s