The angular frequency of the wave is determined as 75.4 rad/s.
<h3>
What is wave function?</h3>
A wave function is a mathematical equation for the motion of the wave.
y(x, t) = A sin(kx + ωt + Φ)
where;
- ω is angular speed
- k is angular wavenumber
- Φ is phase angle
<h3>What is angular frequency?</h3>
The angular frequency is the angular displacement of any wave element per unit of time or the rate of change of the waveform phase.
<h3>Angular frequency</h3>
ω = 2πf
ω = 2π(12)
ω = 75.4 rad/s
Thus, the angular frequency of the wave is determined as 75.4 rad/s.
Learn more about angular frequency here: brainly.com/question/3654452
#SPJ4
The electric field generated by a point charge is given by:

where

is the Coulomb's constant
Q is the charge
r is the distance from the charge
We want to know the net electric field at the midpoint between the two charges, so at a distance of r=5.0 cm=0.05 m from each of them.
Let's calculate first the electric field generated by the positive charge at that point:

where the positive sign means its direction is away from the charge.
while the electric field generated by the negative charge is:

where the negative sign means its direction is toward the charge.
If we assume that the positive charge is on the left and the negative charge is on the right, we see that E1 is directed to the right, and E2 is directed to the right as well. This means that the net electric field at the midpoint between the two charges is just the sum of the two fields:
Answer:
nothing travels faster than light
Example:
You’ll always see lightning before you hear it, because typically lightning will be a mile away, two miles away.
The first rule of vectors is that the horizontal and vertical components are separate. Disregarding air resistance, the only thing we have to worry about is gravity.
The appropriate suvat to use for the vertical component is v = u +at
I will take a to be -9.81, you may have to change it to be 10 if your qualification likes g to be 10.
v = 30 + (-9.81x2)
v = 30 - 19.62
=10.38m/s
Therefore we know that after 2.0 s the vertical component will be 10.38ms^-1, ie 10m/s as the answers given are all to 2sf.
The horizontal component is completely separate to the vertical component and since there is no air resistance, it will remain constant throughout the projectiles trajectory. Therefore it will remain at 40ms^-1.
Combining this together we get:
(1) vx=40m/s and vy=10m/s
Answer:
23 m/s downward
__________________________________________________________
<em>Taking the downward direction as positive</em>
<u>We are given:</u>
Initial velocity of the marble (u) = 0 m/s
Time interval (t) = 2.3 seconds
Final velocity (v) = x m/s
<u>Solving for the Final velocity:</u>
<u>Acceleration of the Marble:</u>
We know that gravity will make the marble accelerate at a constant acceleration of 10 m/s
<u>Final velocity:</u>
v = u + at [First equation of motion]
x = 0 + (10)(2.3) [replacing the given values]
x = 23 m/s
Hence, after 2.3 seconds, the marble will move at a velocity of 23 m/s in the downward direction