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liberstina [14]
3 years ago
8

Observing neutrinos from the Sun is an important way to check the fusion rate, but it can be very tough to build a machine that

can detect these particles. What trouble did the most recent experiment, Borexino, have to overcome
Physics
1 answer:
Vika [28.1K]3 years ago
5 0

Answer:

The trouble that the most recent experiment, Borexino, have to overcome was that

neutrinos hardly interact with matter and so radioactive decay of ant material inside the detector could look exactly like a neutrino interaction too

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It is fine to wear maong pants when preforming physical activity write true or false
vitfil [10]
Nono definitely not (false)
8 0
3 years ago
Read 2 more answers
Read the following story and tell me how Harper used the FITT principle. Harper works out 4-5 days a week for 60 minutes a day.
sweet [91]

Harper used the the frequency principle (F) by planning to work out 4-5 days a week. Frequency is how often you exercise, usually on a weekly basis.

She used the intensity principle (I) by deciding to exercise on a moderate level, rather than, for example, an intense workout. Intensity is basically how hard you exercise and push yourself.

She then used the time (T) principle by choosing to workout for 60 mins per day. Time meaning how much time you spend working out each day.

And lastly, she used the type (T) principle by devising a specific type and/or set of exercise(s) to do, which in her case, is drills, jogging, and weight lifting.

So all in all, Harpers frequency is 4-5 days per week, her intensity is moderate, her time is 60 mins/day, and type is basketball drills, jogging and weight lifting.

Hope I helped! :)

7 0
3 years ago
Sound waves in air travel at approximately 330m/s. Calculate the frequency of a 2.5m-long sound wave.
dusya [7]
Frequency = speed ÷ wavelength
= 330m/s ÷ 2.5m
= 132 Hz
8 0
4 years ago
In an "atom smasher," two particles collide head on at relativistic speeds. If the velocity of the first particle is 0.741c to t
galina1969 [7]

Answer:

W_x = 0.9156\ c

Explanation:

given,

velocity of particle 1 = 0.741 c to left

velocity of second particle = 0.543 c to right

relative velocity between the particle = ?

for the relative velocity calculation we have formula

W_x = \dfrac{|u_x - v_x|}{1-\dfrac{u_xv_x}{c^2}}

u_x = 0.543 c

v_x = - 0.741 c

W_x = \dfrac{0.543 c - (-0.741 c)}{1-\dfrac{(0.543 c)(-0.741 c)}{c^2}}

W_x = \dfrac{0.543 c +0.741 c)}{1+\dfrac{(0.543)(0.741)c^2}{c^2}}

W_x = \dfrac{1.284c}{1+0.402363}

W_x = 0.9156\ c

Relative velocity of the particle is W_x = 0.9156\ c

5 0
3 years ago
Tim and Rick both can run at speed vr and walk at speed vw, with vr>vw. They set off together on a journey of distance D. Ric
g100num [7]

Answer:

Explanation:

1

t = D/2(vw) + D/2(vr)

2

V(ave) = 2.v(r).v(w) / [v(r) + v(w)]

3

t(T) = 2D / [v(w) + v(r)]

4

Tim does

5

3 0
3 years ago
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