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Harlamova29_29 [7]
3 years ago
12

(?,3) is on the line y=2x+5 what is the other coordinate

Mathematics
2 answers:
Dmitriy789 [7]3 years ago
7 0
<h3>♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫</h3>

➷ Substitute it into the equation:

3 = 2x + 5

Subtract 5 from both sides:

-2 = 2x

Divide both sides by 2:

x = -1

The other coordinate is -1

<h3><u>✽</u></h3>

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

suter [353]3 years ago
4 0

Answer:

-1

Step-by-step explanation:

<u>1</u><u>.</u>We know that the equation of the line is <u>y=2x+5</u> ( with a gradient of 2 and a

y-intercept of 5) and the y coordinate is 3 so we must work out x (x,3).

<u>2.</u>We know<u> y=3</u> so

3 = 2x+5

 

<u>3.</u> <u>Solve the equation</u>

3=2x+5

(-5 from both sides)

-2=2x

(Divide both sides by 2 to isolate x)

-1 = x so x = 1

Hope this helps:)

5INGH

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3 years ago
a. Fill in the midpoint of each class in the column provided. b. Enter the midpoints in L1 and the frequencies in L2, and use 1-
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\begin{array}{ccc}{Midpoint} & {Class} & {Frequency} & {64} & {63-65} & {1}  & {67} & {66-68} & {11} & {70} & {69-71} & {8} &{73} & {72-74} & {7}  & {76} & {75-77} & {3} & {79} & {78-80} & {1}\ \end{array}

Using the frequency distribution, I found the mean height to be 70.2903 with a standard deviation of 3.5795

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Given

See attachment for class

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Lower \to Lower class interval

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Class 66 - 68:

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\begin{array}{ccc}{Midpoint} & {Class} & {Frequency} & {64} & {63-65} & {1}  & {67} & {66-68} & {11} & {70} & {69-71} & {8} &{73} & {72-74} & {7}  & {76} & {75-77} & {3} & {79} & {78-80} & {1}\ \end{array}

Solving (b): Mean and standard deviation using 1-VarStats

Using 1-VarStats, the solution is:

\bar x = 70.2903

\sigma = 3.5795

<em>See attachment for result of 1-VarStats</em>

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3 years ago
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