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Andrej [43]
4 years ago
9

What is the volume of a tank of nitrogen if it contains 17 moles of nitrogen at 34 C under 12,000 Pa?

Chemistry
1 answer:
nydimaria [60]4 years ago
6 0
To answer this question, we must use an equation that relates all of this information. The one that we need to use is the Ideal Gas Law, PV=nRT. However, to calculate properly, we will need to convert some of the numbers to different units so that the equation is usable. Change Celsius to Kelvin and change Pascals to atmospheres (1 atm = 101300 Pa) and we can substitute and simplify:

PV = nRT
(0.1185 atm)V = (17 mol)(0.0821 L•atm/K•mol)(307.15 K)
0.1185V = 428.689
V = 3617.63 L

The question asks for cubic meters, and 1,000 liters equals 1 m^3. Simply divide the answer by 1,000.

The volume that this would occupy is B, 3.62 m^3.

Hope this helps!
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Explanation:

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+<br>|<br>+<br>+<br>that this atom is neutral? <br>​
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6 0
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Read 2 more answers
A 0.4657 g sample of a pure soluble bromide compound is dissolved in water, and all of the bromide ion is precipitated as AgBr b
Yanka [14]

Answer:

The mass percentage of bromine in the original compound is 81,12%

Explanation:

<u>Step 1: Calculate moles AgBr</u>

moles AgBr = mass AgBr / molar mass  AgBr

= 0.8878 g / 187.77 g/mol

= 0.00472812 moles AgBr

⇒

Since 1 mol AgBr contains 1 mol Br-

Then the amount of moles Br- in the original sample must also have  been 0.00472812 moles

<u>Step 2:</u> Calculating mass Br-

mass Br- = molar mass Br x moles  Br-

= 79.904 g/mol x 0.00472812 mol

= 0.377796 g Br-

⇒

There were 0.377796 g Br- in the original sample

<u>Step 3:</u> Calculating mass percentage Br-

⇒mass percentage  = actual mass Br- / total mass x 100%

% mass Br = 0.377796 g / 0.4657 g x 100  %

= 81.12%

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3 years ago
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