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gtnhenbr [62]
4 years ago
6

AgNO3 + NaCl mc017-1.jpg NaNO3 + AgCl

Chemistry
2 answers:
lina2011 [118]4 years ago
8 0

The balanced reaction is:

 AgNO3 + NaCl = NaNO3 + AgCl

 <span>We are given the amount of silver nitrate to react with sodium chloride. This will be our starting point.</span>

 15.0 mol AgNO3 (1 mol AgCl / 1 mol AgNO3 ) =15.0 mol AgCl


The amount of moles produced is the same with the amount of the given reactant since they only one is to one ratio.

Juli2301 [7.4K]4 years ago
8 0

<u>Answer:</u> 15 moles of silver chloride will be produced.

<u>Explanation:</u>

We are given:

Moles of silver nitrate = 15 moles

For the given chemical reaction:

AgNO_3+NaCl\rightarrow NaNO_3+AgCl

By Stoichiometry of the reaction:

1 mole of silver nitrate produces 1 mole of silver chloride.

So, 15 moles of silver nitrate will produce = \frac{1}{1}\times 15=15mol of silver chloride.

Hence, 15 moles of silver chloride will be produced.

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there's no picture here but I guess the answer would be:

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3 0
3 years ago
Select the correct answer.
Step2247 [10]

Answer:

Vanadium(V) oxide is the inorganic compound with the formula V2O5. Commonly known as vanadium pentoxide,

Explanation:

then it is answer D

5 0
3 years ago
Suppose you are working with a NaOH stock solution but you need a solution with a lower concentration for your experiment. Calcu
Monica [59]

Answer: The volume of the 1.224 M NaOH solution needed is 26.16 mL

Explanation:

In order to prepare the dilute NaOH solution, solvent is added to a given amount of the NaOH stock solution up to a final volume of 250.0 mL.

Since only solvent is added, the amount of the solute, NaOH, in the dilute solution is the same as in the volume taken from the stock solution.

Molarity (<em>M)</em> is calculated from the following equation:

<em>M</em> = <em>n</em> ÷ <em>V</em>

where <em>n</em> is the number of moles of the solute in the solution, and <em>V</em> is the volume of the solution.

Accordingly, the number of moles of the solute is given by

<em>n</em> = <em>M</em> x <em>V</em>

Now, let's designate the stock NaOH solution and the dilute solution as (1) and (2), respectively . The number of moles of NaOH in each of these solutions is:

<em>n </em>(1) = <em>M </em>(1) x <em>V </em>(1)

<em>n </em>(2) = <em>M </em>(2) x <em>V </em>(2)

As the amount of NaOH in the dilute solution is the same as in the volume taken from the stock solution,

<em>n</em> (1) = <em>n</em> (2)

and

<em>M</em> (1) x <em>V</em> (1)<em> </em>= <em>M</em> (2) x <em>V</em> (2)

For the stock solution, <em>M</em> (1) = 1.244 M, and <em>V</em> (1) is the volume needed. For the dilute solution, <em>M</em> (2) = 0,1281 M, and <em>V</em> (2) = 250.0 mL.

The volume of the stock solution needed, <em>V</em> (1), is calculated as follows:

<em>V</em> (1) = <em>M</em> (2) x <em>V</em> (2) ÷ <em>M</em> (1)

<em>V</em> (1) = 0.1281 M x 250.0 mL ÷ 1.224 M

<em>V </em>(1) = 26.16 mL

The volume of the 1.224 M NaOH solution needed is 26.16 mL.

7 0
3 years ago
Question 2 (0 points)
bazaltina [42]

Answer:

The probability  of spinning red with the spinner or rolling an odd number with the  die is \dfrac{1}{8}

Explanation:

Given that,

Total color in spinner = 4

Let the area of four parts is equal in the spinner.

We need to calculate the probability of spinning red

Using formula of probability

P(A) = \dfrac{Number\ of\ red\ color\ outcome}{Total\ number\ of\ colors\ in\ the\ spinner}

Put the value into the formula

P(A)=\dfrac{1}{4}

We need to calculate the probability of odd number of the die

Using formula of probability

P(B) = \dfrac{Number\ of\ odd\ digits\ outcome}{Total\ number\ of\ digits\ in\ the\ die}

Put the value into the formula

P(B)=\dfrac{3}{6}

P(B)=\dfrac{1}{2}

We need to calculate the probability  of spinning red with the spinner or rolling an odd number with the  die

Using formula of probability of two events which is independent

P(A\ and\ B)=P(A)\times P(B)

Put the value into the formula

P(A\ and\ B)=\dfrac{1}{4}\times\dfrac{1}{2}

P(A\ and\ B)=\dfrac{1}{8}

Hence, The probability  of spinning red with the spinner or rolling an odd number with the  die is \dfrac{1}{8}

5 0
3 years ago
1. What is the molarity of a solution prepared by dissolving 3.11 grams of NaOH in
Elena L [17]

The molarity of a solution prepared by dissolving 3.11 grams of NaOH in

enough water to make 300 milliliters of solution is 0. 256 mol/ L

Explanation:

<h3>What is Molarity?</h3>

Molarity (M) is the amount of a substance in a given volume of solution. It is otherwise known as the number of moles of solute in a certain amount of solution.

The unit of molarity is mol/L

<h3>Formula for calculating molarity :</h3>

Molarity = number of moles of solute divided by the volume of the solution\

<h3>Parameters </h3>

Molarity = ?

Number of  moles is calculated using :

Mass of the solute = 3.11 grams of NaOH

Molar mass of the solute = Na + O + H

Let's input the atomic numbers of the elements: Na (23) , O (16) , H (1)

Molar mass of NaOH = 23 + 16 + 1 = 40 g/ mol

Number of moles = 3.11 ÷ 40 = 0.077 mol

Volume of the solution is measured in Liters

Let's convert 300 milliters to liters = 300 divided by 1000 = 0.3 Liters

Molarity = 0.077 ÷ 0.3 = 0. 256 mol/ L

Therefore, the Molarity of the solution is 0. 256 mol/ L

Read more on molarity here :

brainly.com/question/26873446

3 0
2 years ago
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