Answer:

Explanation:
-Specific heat capacity is given by the formula:

Where:
is the heat gained or loosed by the substance
is the mass of the substance
is the specific heat of the substance
is the change in temperature
#We make c the subject of the formula and substitute to solve for it:

Hence, the specific heat capacity of the ice is 
Answer:
Functional groups.
Explanation:
Functional groups are the specific substituents present within the molecules which are responsible for characteristic chemical properties the molecule shows.
Glucose contains alcohol and aldehyde group while hexanoic acid contains carboxylic acid group. <u>The presence different types of the functional groups in both the compounds results in the difference in the properties of both the compounds.</u>
Complete balanced equation: 2HNO₃ + Ca(OH)₂ → Ca(NO₃)₂ + 2H₂O
Ionized equation (with spectator ions):
2H⁺ + 2NO₃⁻ + Ca²⁺ + 2OH⁻ → Ca²⁺ + 2NO₃⁻ + 2H₂O
By eliminating the ions that are the same of both sides of the equation (spectator ions):
2H⁺ + 2OH⁻ → 2H₂O [Net Ionic Equation]
Answer:

Explanation:
Hello,
In this case, for the dissociation of calcium fluoride:

The equilibrium expression is:
![Ksp=[Ca^{2+}][F^-]^2](https://tex.z-dn.net/?f=Ksp%3D%5BCa%5E%7B2%2B%7D%5D%5BF%5E-%5D%5E2)
In such a way, via the ICE procedure, including an initial concentration of calcium of 0.01 M (due to the calcium nitrate solution), the reaction extent
is computed as follows:

Thus, the molar solubility equals the reaction extent
, therefore:

Regards.