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navik [9.2K]
3 years ago
6

BRAINLIEST!!!!!! PLEASE HELP ASAP!!!!!! PLEASE ANSWER THESE!!!!! PLEASE DON'T SPAM!!!!!.​

Chemistry
1 answer:
Len [333]3 years ago
4 0

Answer:

Explanation: wht do i do??

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The table below compares the radioactive decay rates of two materials. Material Original mass of material (in grams) Mass of mat
Hoochie [10]

Answer:

The half-life of Material 1 and Material 2 are equal.

Explanation:

Material 1 disintegrates to half its mass three times in 21.6 s, to go from 100g

to 12.5g. That is,

100g - 50g - 25g - 12.5g

Material 2 disintegrates to half its mass three times in 21.6 s, to go from 200g to 25g. That is,

200g - 50g - 25g - 12.5g.

This means that regardless of their initial masses involved, material 1 and material 2 have equal half-life.

Their half-life is 21.6 ÷ 3 = 7.2 sec

5 0
4 years ago
In which block of the periodic table is chromium (Cr) found?
Crank
It’s found in the d-block
7 0
4 years ago
Helium is located in group 8A but does not have eight valence electrons. Why is it located in 8A, not 2A?
astraxan [27]

Answer:

its outermost shell is completely full making it extremely stable.

Explanation:

It only has two electrons in its outer shell so its valence electron configuration is 1s2. Even though it only has two electrons, it is grouped with elements that have eight valence electrons. Helium is still happy because its outermost shell is completely full making it extremely stable.

5 0
3 years ago
What is the mass number of C12,C13 and C14
Elena L [17]
Carbon-13 and Carbon-14 are isotopes of the element carbon. All carbon atoms have 6 protons in their nucleus and most have 6 neutrons. Since the mass number consists of # of protons + # of neutrons, Carbon 12 has an atomic mass of 12 ( = 6 protons + 6 neutrons). Carbon-13 atoms have one extra neutron, giving it a total of 7 neutrons. Carbon-14 atoms have two extra neutrons, giving them a total of 8 neutrons. Therefore the mass number of C-12= 12, C-13= 13 and C-14= 14.
3 0
4 years ago
Calculate the mass of oxygen (in mg) dissolved in a 5.00 L bucket of water exposed to a pressure of 1.13 atm of air. Assume the
REY [17]

Explanation:

It is known that relation between partial pressure, mole fraction and pressure is as follows.

      Partial pressure of gas = mole fraction of gas × Pressure of gas

Therefore, putting the given values into the above formula as follows.

   Partial pressure of gas = mole fraction of gas × Pressure of gas

                                          = 0.21 \times 1.13 atm

                                           = 0.237 atm

According to Henry's law,

       Concentration of oxygen = Henry's law constant × partial pressure of oxygen

             = 1.3 \times 10^{-3} M/atm \times 0.2373 atm

             = 3.08 \times 10^{-4} M

Therefore, calculate moles of oxygen in 5.00 L present as follows.

   Moles of oxygen in 5.00 L = volume × concentration

                                                 = 5.00 \times 3.0849 \times 10^{-4}

                                                 = 1.542 \times 10^{-3} mol

Now, we will calculate the mass of oxygen as follows.

        Mass of oxygen = moles × molar mass of oxygen

                                    = 1.542 \times 10^{-3} mol \times 32 g/mol mol    

                                    = 0.0494 g

or,                                 = 49.4 mg           (As 1 g = 1000 mg)

thus, we can conclude that the mass of given oxygen (in mg) is 49.4 mg.

5 0
3 years ago
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