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4 years ago

Utilizing dimensional analysis find the number of inches in a kilometer given that 1 inch equals 2.54 cm

1 answer:

4 0

To solve this problem, separate it into chunks that you know. You know that there are 2.54 centimeters in 1 inch. You know that there are 100 centimeters in 1 meter. You know that there are 1000 meters in a kilometer. Therefore, we'll convert in this order: 1) from kilometers to meters, 2) from meters to centimeters, and 3) from centimeters to inches.
1) 1km × 1000m/1km
= 1000m
2) 1000m × 100cm/1m
= 100000cm
3) 100000cm × 1in/2.54cm
≈ 39370in
So, there are approximately 39370 inches in a kilometer.

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Calculate the ionic strength of a solution of iron (iii) carbonate, fe2(co3)3 of concentration 0.020 mol dm

Ede4ka [16]

E=b(x^3)×co3x{fe2}+13^3

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3 years ago

Write the molecular formula for the following compound.<br>

Sholpan [36]

Answer : The molecular formula of the compound is, $C_8H_9O_3N$

Explanation :

Molecular formula : It is the representation of substance by the symbols and it denotes the number of atoms of each element present in the compound.

Now count the number of carbon, hydrogen, nitrogen and oxygen atoms present in the given compound.

As we see that in the given compound, there are 8 atoms of carbon element, 3 atoms of oxygen element, 1 atom of nitrogen element, 9 atoms of hydrogen element.

Thus, the molecular formula of the compound will be $C_8H_9O_3N$

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3 years ago

What is an exotoxin?

Elodia [21]

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3 years ago

Methanol (ch3oh), also called methyl alcohol, is the simplest alcohol. it is used as a fuel in race cars and is a potential repl

erica [24]

Answer:

%age Yield = 51.45 %

Solution:

Step 1: Convert Kg into g

68.5 Kg CO = 68500 g CO

8.60 Kg H₂ = 8600 g

Step 2: Find out Limiting reactant;

The Balance Chemical Equation is as follow;

CO + 2 H₂ → CH₃OH

According to Equation,

28 g (1 mol) CO reacts with = 4 g (2 mol) of H₂

So,

68500 g CO will react with = X g of H₂

Solving for X,

X = (68500 g × 4 g) ÷ 28 g

X = 9785 g of H₂

It shows 9785 g H₂ is required to react with 68500 g of CO but we are provided with 8600 g of H₂ which is less than required. Therefore, H₂ is provided in less amount hence, it is a Limiting reagent and will control the yield of products.

Step 3: Calculate Theoretical Yield

According to equation,

4 g (2 mol) H₂ reacts to produce = 32 g (1 mol) Methanol

So,

8600 g H₂ will produce = X g of CH₃OH

Solving for X,

X = (8600 g × 32 g) ÷ 4 g

X = 68800 g of CH₃OH

Step 4: Calculate %age Yield

%age Yield = Actual Yield ÷ Theoretical Yield × 100

Putting Values,

%age Yield = 3.54 × 10⁴ g ÷ 68800 g × 100

%age Yield = 51.45 %

5 0

4 years ago

Three mixtures were prepared from three very narrow molar mass distribution polystyrene samples with molar masses of 10,000, 30,

8_murik_8 [283]

Answer:

(a). 46,666.7 g/mol; 78,571.4 g/mol

(b). 86950g/mol; 46,666.7 g/mol.

(c). 86950g/mol; 43,333.33 g/mol

Explanation:

So, we are given the molar masses for the three samples as: 10,000, 30,000 and 100,000 g mol−1.

Thus, the equal number of molecule in each sample = ( 10,000 + 30,000 + 100,000 ) / 3 = 46,666.7 g/mol.

The average molar mass = [ ( 10,000)^2 + (30,000)^2 + 100,000)^2] ÷ 10,000 + 30,000 + 100,000 = 78,571. 4 g/mol.

(b). The equal masses of each sample = 3/[ ( 1/ 10,000) + (1/30,000 ) + (1/100,000) ] = 20930.23 g/mol.

Average molar mass = ( 10,000 + 30,000 + 100,000 ) / 3 = 46,666.7 g/mol.

(c). Equal masses of the two samples = (0.145 × 10,000) + (0.855 × 100,000)/ 0.145 + 0.855 = 86950g/mol.

The weight average molar mass = 1.7 + 10,000 + 100,000/ 1.7 + 1 = 43,333.33 g/mol.

6 0

3 years ago