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2 years ago

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Which are negative impacts that the internal combustion engine has had on society?

A.High power and health problems B.noise pollution and health problems C.efficient travel and noise pollution D.efficient travel and high power

1 answer:

Natasha2012 [34]2 years ago

7 0

<u>B. Noise Pollution and health problems</u><u /> the only answer with 2 negatives and no positives.

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If it takes Jupiter 13 years to orbit the Sun. How long (in years) will it take Jupiter to go once around the sky as viewed from

irakobra [83]

We have that the time it will take Jupiter to around the sky is mathematically given as

Psyn=295days

<h3>Time for Jupiter to around the sky</h3>

Question Parameters:

If it takes Jupiter 13 years to orbit the Sun.

Generally, The earth moved a bit further, one Jupiter period ago, This is called synodic period

$Psyn=\frac{psid}{Psid-1}\\\\Psyn=\frac{13}{13-1`}\\\\Psyn=1.08year\\\\$

Psyn=295days

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1 year ago

A printer has a power of 100 W. It takes 30 seconds to print out a document. How much energy will it

Black_prince [1.1K]

100W translates to 100 watts consumed in 1 hour. Assuming the printer consumes electrical energy at a steady rate, then: 100 ÷ 60 = 1.6667 watts per minute. 1.6667 ÷ 2 = 0.8333 watts consumed in 30 seconds.

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2 years ago

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Does energy or matter ever disappear? Explain.

maria [59]

Answer:

The first law of thermodynamics doesn't actually specify that matter can neither be created nor destroyed, but instead that the total amount of energy in a closed system cannot be created nor destroyed (though it can be changed from one form to another).

Explanation:

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3 years ago

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In the ground state of hydrogen, according to the Bohr model, an electron orbits 5.3 x 10-11 m from the nucleus. It undergoes a

Readme [11.4K]

Answer:

Explanation:

Given

radius of electron $(r)=5.3\times 10^{-11} m$

centripetal acceleration $(a_c)=9\times 10^22 m/s^2$

we know

$a_c=\frac{v^2}{r}$

$v=\sqrt{r\times a_c}$

$v=\sqrt{5.3\times 10^{-11}\times 9\times 10^{22}}$

$v=\sqrt{47.7\times 10^11}$

$v=21.84\times 10^5 m/s$

(b)For n=10

$r=100\times 5.3\times 10^{-11} m\approx 5.3\times 10^{-9} m$

$a_c=10^4\times 9\times 10^{22} m/s^2$

$a_c=9\times 10^{26} m/s^2$

$v=\sqrt{r\times a_c}$

$v=\sqrt{9\times 10^{26}\times 5.3\times 10^{-9}}$

$v=21.84\times 10^8 m/s$

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3 years ago

Consider the following arrangement with a frictionless/massless pulley. Determine the force F required to move block A if the co

Delicious77 [7]

Answer: The free - body diagrams for blocks A and B. frictionless surface by a constant horizontal force F = 100 N. Find the tension in the cord between the 5 kg and 10 kg blocks. The string that attaches it to the block of mass M2 passes over a frictionless pulley of negligible mass. The coefficient of kinetic friction Hk between M.

Explanation: Hope this helped :)

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2 years ago