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Novosadov [1.4K]
2 years ago
5

A 8.2-V battery is connected in series with a 38-mH inductor, a 150-Ω resistor, and an open switch.A 8.2-V battery is connected

in series with a 38-mH inductor, a 150-Ω resistor, and an open switch. Part A
What is the current in the circuit 0.110 ms after the switch is closed? unit (mA)
Part B
How much energy is stored in the inductor at this time? unit(micro J)
Physics
1 answer:
tigry1 [53]2 years ago
8 0

Answer:

(A). The current in the circuit is 19.25 mA.

(B). The store energy in the inductor is 7.04 μJ.

Explanation:

Given that,

Voltage = 8.2 V

Inductor = 38 mH

Resistance = 150 Ω

Time t = 0.110 ms

The battery has negligible internal resistance, so that the total resistance  in the circuit is 150 ohms. Then use this equation for current at time t in terms of inductance

We need to calculate the current

Using formula of current

I(t)=\dfrac{V}{R}\times(1-e^{-t\times\dfrac{R}{L}})

Put the value into the formula

I(t)=\dfrac{8.2}{150}\times(1-e^{-0.110\times10^{-3}\times\dfrac{150}{38\times10^{-3}}})

I(t)=0.01925\ A

I(t) = 19.25\ mA

(B). We need to calculate the store energy in the inductor

Using formula of energy

E=\dfrac{1}{2}LI^2

Put the value into the formula

E=\dfrac{1}{2}\times38\times10^{-3}\times(0.01925)^2

E=7.04\times10^{-6}\ J

{tex]E=7.04\ \mu J[/tex]

Hence, (A). The current in the circuit is 19.25 mA.

(B). The store energy in the inductor is 7.04 μJ.

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Explanation:

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Two identical point charges are 3.00 cm apart. find the charge on each of them if the force or repulsion is 4.00 x 10^-7. (Use C
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Explanation:

We know that Force between two point charges is given b the Coulomb's law as:

F = kq₁q₂/r^2

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r = 3.00 cm

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F = 4.00 x 10^-7

Rearranging the formula, we get:

F = k q²/r²

q² = Fr²/k

q² = 4 x 10⁻⁷ x 0.03²/(9x10⁹)

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As there is force of repulsion between the charges, the charges must be both positive or both negative.

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A runner is moving at a constant speed of 8.00 m/s around a circular track. If the distance from the runner to the center of the
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Answer: Last option

2.27 m/s2

Explanation:

As the runner is running at a constant speed then the only acceleration present in the movement is the centripetal acceleration.

If we call a_c to the centripetal acceleration then, by definition

a_c =w^2r = \frac{v^2}{r}

in this case we know the speed of the runner

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r = 28.2\ m

a_c = \frac{8^2}{28.2}\ m/s^2

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3 years ago
Question 4 - If Angelica starts out at 30m/s, and in 16 s speeds up to 84 m/s, what is her acceleration?
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Answer:

C. 3.375 m/s^2

Explanation:

The acceleration of an object can be found using the equation:

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u = 30 m/s is the initial velocity of Angelica

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Substituting into the equation, we find the acceleration:

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