In the crystal structure of potassium oxide, the oxide ions are coordinated by eight potassium ions. part a what is the coordina
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Answer:
6.25e-6 is the value of the equilibrium constant
Explanation:
we have this equation
When at a state of equilibrium,
we have the concentration of Pb^2+ to be 0.01
we have the concentration of Br^- to be 0.025
the equilibrium constant concentration of both pure solids and liquid s are said to be equal to 1
[PbBR2] = 1
such tht
Keq = [Pb^2+] x [Br-]^2
we already know the values of these from the above.
0.01x0.025^2
= 0.01 x 0.000625
= 0.00000625
= 6.25 x 10^-6
= 6.25e^-6
The energy for the transition:
The energy for the transfer of an electron from the n=2 level to the n=5 level of a hydrogen atom is 4.57 x J
Calculation:
We are aware of the energy levels as n=2 and n=5. So, we may determine the wavelength of the photon released by the electron during this transition using Rydberg's equation:
1/λ = R x (1/ - 1/
)
where,
1/λ = the wavelength of the emitted photon,
R = Rydberg's constant, 1.0974 x
= the final energy level = 5
= the initial energy level = 2
Now, put the value in the above equation, we get,
1/λ = 1.0974 x x ( 1/
- 1/
)
1/λ = 1.0974 x x (-0.21)
1/λ = -0.23 x
λ = 4.347 x m
Since, E = hc/λ
where,
h = Plank's constant = 6.626 x Js
c = speed of light = 3 x m/s
So, the transition energy for your particular transition is,
E = 6.626 x x 3 x
/ (4.347 x
)
E = 4.57 x J
Learn more about Rydberg's formula here,
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