Question

Write the ratio for sin A and cos A. The triangle is not drawn to scale.

Answer 1

Option A:

$\sin A= \frac{14}{50}, \ \cos A= \frac{48}{50}$

Solution:

Given data:

AB = 50, BC = 48, AC = 14

To find the value of sin A and cos A:

$\sin A= \frac{Opposite \ side}{Hypotenuse}$

$\sin A= \frac{AC}{AB}$

$\sin A= \frac{14}{50}$

$\cos A= \frac{Adjacent \ side}{Hypotenuse}$

$\cos A= \frac{BC}{AB}$

$\cos A= \frac{48}{50}$

$\therefore \ \sin A= \frac{14}{50}, \ \cos A= \frac{48}{50}$

Hence option A is the correct answer.