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kramer
3 years ago
13

1. A 15 feet tree casts a shadow that is 8 feet long. What is the distance from the tip of the tree to the tip of its

Mathematics
1 answer:
natka813 [3]3 years ago
7 0

Answer:

the answer is 17 feet

Step-by-step explanation:

you have to use the pythagorean theorem.

a^{2} + b^{2} = c^{2}

for a is 15 and b is 8

15^{2} + 8^{2} = 289

289 = c\^{2}

\sqrt{289} = 17

therefore, the distance is 17 feet.

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Find the distance between the points T(13, 1.6) and V(5.4.3.7).
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Find the distance between the points t(13, 1.6)t(13, 1.6) and v(5.4, 3.7)v(5.4, 3.7).

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The distance between any 2 points P(a,b) and Q(c,d) in the coordinate plane, is given by the formula:

Thus the distance between points t(13, 1.6) and v(5.4, 3.7) is found using the formula as:

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2 years ago
What is the value of this expression when b=5?<br><br> 6(2b-4)
Taya2010 [7]
6(2(5) - 4)
6(10 - 4)
6(6)
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3 years ago
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Tom [10]

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What is the first operation you start with when solving
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Solve the Law of Cosine: c^2 = a^2+ b^2 - 2abcosC for cos C.
Andrew [12]

Answer:

The Law of Cosine :  cos C = \frac{a^{2}+ b^{2}-c^{2}}{2ab}

Step-by-step explanation:

See the figure to understand the proof :

Let A Triangle ABC with sides a,b,c,

Draw a perpendicular on base AC of height H meet at point D

Divide base length b as AD = x -b   and    CD = x

By Pythagoras Theorem

In Triangle BDC             And     In Triangle BDA

a² = h² + x²     (  1  )                        c² = h² + (x-b)²

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From above eq 1 and 2

c² = (a² - x²) + x² + b² - 2xb

or, c² = a² + b² - 2xb                    .....(3)

Again in ΔBDC

cos C = \frac{BD}{BC}

Or, cos C = \frac{x}{a}

∴ x= a cos C

Now put ht value of x in eq 3

I.e, c² = a² + b² - 2ab cos C

Hence , cos C = \frac{a^{2}+ b^{2}-c^{2}}{2ab}      Proved   Answer

6 0
2 years ago
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