<h3>
Answer: 7/10</h3>
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Explanation:
There are 30 days in April. Since it rained 9 of those days, the empirical probability of it raining in April is 9/30 = (3*3)/(3*10) = 3/10.
If we assume that the same conditions (ie weather patterns) hold for May, then the empirical probability of it raining in May is also 3/10. By "raining in May", I mean specifically raining on a certain day of that month.
The empirical probability of it not raining on the first of May is therefore...
1 - (probability it rains)
1 - (3/10)
(10/10) - (3/10)
(10-3)/10
7/10
We can think of it like if we had a 10 day period, and 3 of those days it rains while the remaining 7 it does not rain.
Sin50° = BC/3
3sin50° = BC
BC = 2.981
Hope this helped!
Answer:
299 miles per hour
Step-by-step explanation:
![v=\frac{234}{\sqrt[3]{\frac{p}{w}}}](https://tex.z-dn.net/?f=v%3D%5Cfrac%7B234%7D%7B%5Csqrt%5B3%5D%7B%5Cfrac%7Bp%7D%7Bw%7D%7D%7D)
![v=\frac{234}{\sqrt[3]{\frac{1311}{2744}}}](https://tex.z-dn.net/?f=v%3D%5Cfrac%7B234%7D%7B%5Csqrt%5B3%5D%7B%5Cfrac%7B1311%7D%7B2744%7D%7D%7D)
Therefore, the velocity of the car at the end of a drag race is 299 miles per hour
y + (2x -12) = 180 (since they are supplementary angles)
(2x-12) = 96 ( since they are alternate exterior angle)
2x = 96 + 12
2x = 108
x = 108/2
x = 54.
y+( 2x-12)=180
y+(2× 54 -12) = 180
y + (108-12) = 180
y + 96 = 180
y= 180-96
y = 84.
