All categories

2 years ago

Find the distance between the points R(0,1) and S(6,3.5)

Mathematics

1 answer:

Genrish500 [490]2 years ago

5 0

Answer:

Step-by-step explanation:

=(3)2+(5.5)2‾‾‾‾‾‾‾‾‾‾‾‾√

d=(3)2+(5.5)2

=9+30.25‾‾‾‾‾‾‾‾‾√

d=9+30.25

=3‾√9.25

d=39.25

=6.264982

You might be interested in

What are the coordinates of the point X'if the image is rotated 90° counter clockwise

Wewaii [24]

Step-by-step explanation:

When rotating a point 90 degrees counterclockwise about the origin our point A(x,y) becomes A'(-y,x). In other words, switch x and y and make y negative

3 0

2 years ago

Initial value problems dy/dx+2y=3. Y(0)=1

Pavel [41]

The initial value equation is $y = \frac 12(3 - e^{-2x})$

<h3>How to solve the initial value?</h3>

The equation is given as:

$\frac{dy}{dx} +2y = 3$

Where

Y(0) = 1

Subtract 2y from both sides in the equation

$\frac{dy}{dx} = -2y + 3$

Rewrite as:

$\frac{dy}{-2y + 3} = dx$

Integrate both sides of the equation

$-\frac 12\ln|-2y + 3| = x + C_o$

Multiply through by -2

$\ln|-2y + 3| = -2x + C_1$

Take the exponent of both sides

$-2y + 3 = Ce^{-2x$

Next, we solve for C under the initial condition Y(0) = 1.

This gives

$-2(1) + 3 = Ce^{-2 * 0$

Evaluate

-2 + 3 = C

Solve for C

C = 1

Substitute C = 1 in $-2y + 3 = Ce^{-2x$

$-2y + 3 = e^{-2x$

Next, we solve for y

$y = \frac 12(3 - e^{-2x})$

Hence, the initial value equation is $y = \frac 12(3 - e^{-2x})$

Read more about initial value at:

brainly.com/question/16945606

#SPJ1

3 0

1 year ago

The fifth grade class at brookfield school used 5 identical buses to go on field trips. How many adults went on the field trip w

viva [34]

Is there more to the problem? There isn’t enough information here.

8 0

3 years ago

Help please due in 20 minutes I will mark brainliest

navik [9.2K]

Answer:

its the second one down my dude. good luck!

6 0

3 years ago

NEED ANSWER ASAP!!!!

lesya692 [45]

Answer:

1st option

Step-by-step explanation:

To find the difference of the given matrices, we just need to subtract the corresponding elements of the two matrices as shown below:

$\left[\begin{array}{cc}-4&8\\3&12\end{array}\right] -\left[\begin{array}{cc}2&1\\-14&15\end{array}\right] \\\\ \\ =\left[\begin{array}{cc}-4-2&8-1\\3-(-14)&12-15\end{array}\right]\\\\ \\ =\left[\begin{array}{cc}-6&7\\17&-3\end{array}\right]$

Thus, 1st option gives the correct answer

7 0

3 years ago

Read 2 more answers