Answer:
The probability that the aircraft is overload = 0.9999
Yes , The pilot has to be take strict action .
Step-by-step explanation:
P.S - The exact question is -
Given - Before every flight, the pilot must verify that the total weight of the load is less than the maximum allowable load for the aircraft. The aircraft can carry 37 passengers, and a flight has fuel and baggage that allows for a total passenger load of 6,216 lb. The pilot sees that the plane is full and all passengers are men. The aircraft will be overloaded if the mean weight of the passengers is greater than 6216/37 = 168 lb. Assume that weight of men are normally distributed with a mean of 182.7 lb and a standard deviation of 39.6.
To find - What is the probability that the aircraft is overloaded ?
Should the pilot take any action to correct for an overloaded aircraft ?
Proof -
Given that,
Mean, μ = 182.7
Standard Deviation, σ = 39.6
Now,
Let X be the Weight of the men
Now,
Probability that the aircraft is loaded be
P(X > 168 ) = P(
)
= P( z >
)
= P( z > -0.371)
= 1 - P ( z ≤ -0.371 )
= 1 - P( z > 0.371)
= 1 - 0.00010363
= 0.9999
⇒P(X > 168) = 0.9999
As the probability of weight overload = 0.9999
So, The pilot has to be take strict action .
530 miles are travelled for every hour passed?
Answer:
1 is the answer because 4^10=1048576 and you have that on the top and the bottom of the problem then 7^0=1 so therefore 1048576/1048576=1
Step-by-step explanation:
Answer:
The monetary choices for Ivy’s lunches is to spend less than $16.67 at restaurants and to spend less than $33.33 on groceries in order to to keep her weekly budget to less than $50.
Step-by-step explanation:
This can be determined as follows
x = the amount of dollars spent at restaurants
y = the amount of dollars spent on groceries
Since Ivy decides that she wants to spend at least twice as much on bagged lunches as at restaurants, we have
y = 2x .................. (1)
Since Ivy wants to keep her weekly budget to less than $50, using the x and y, we have:
x + 2x < 50 ............................ (2)
We can now solve for x as follows:
3x + < 50
x < 50 / 3
x < 16.67
Substituting the x < 17 into equation (1) noting that Ivy wants to keep her weekly budget to less than $50, we have:
y < 2 * 16.67
y < 33.33
Therefore, the monetary choices for Ivy’s lunches is to spend less than $16.67 at restaurants and to spend less than $33.33 on groceries in order to to keep her weekly budget to less than $50.
Answer:
C
Step-by-step explanation: