Answer:
The answer to your question is Mercury
Explanation:
The flame test essay is used to identify the identity of a substance because most elements show different colors when in flame.
There are many elements that burn violet when in flame especially elements of the group IA like Potassium, Rubidium, Cesium and also Cyanide and Mercury located in different groups.
But the bibliography tells us that Mercury chloride burns violet so this element is the correct answer because there is chloride in the sample of this question.
Answer:
When writing equation the mass on left side of equation must be equal to the mass on right side. True
Explanation:
The chemical reactions always follow the law of conservation of mass.
Law of conservation of mass:
According to the law of conservation mass, mass can neither be created nor destroyed in a chemical equation.
Explanation:
This law was given by french chemist Antoine Lavoisier in 1789. According to this law mass of reactant and mass of product must be equal, because masses are not created or destroyed in a chemical reaction.
For example:
In photosynthesis reaction:
6CO₂ + 6H₂O + energy → C₆H₁₂O₆ + 6O₂
there are six carbon atoms, eighteen oxygen atoms and twelve hydrogen atoms on the both side of equation so this reaction followed the law of conservation of mass because total mass is equal on both side of equation.
The correct answer is letter C. Rock Cycle. Living organisms involved in carbon cycle, oxygen cycle, and in nitrogen cycle. These are involved in the air that living organisms are taking in and out.
Answer:
Temporary in nature.
No new substance is formed.
Explanation:
Temporary in nature: Does not affect the internal structure of a substance, only the molecules are rearranged.
No new substance is formed: Most of the physical changes are reversible. We can obtain the substance back even after the change.
hope this helps
have an awesome day -TJ
Answer:
0.1113 mol
Explanation:
Data Given:
no. of atoms of CH₄= 6.70 x 10²² atoms
no. of moles of methane (CH₄) = ?
Solution:
we will find no. of moles of methane (CH₄)
Formula used
no. of moles = no. of atoms / Avogadro's number
Where
Avogadro's number = 6.022 x 10²³
Put values in above equation
no. of moles = 6.70 x 10²² atoms / 6.022 x 10²³ (atoms/mol)
no. of moles = 0.1113 mol
So,
There are 0.1113 moles of methane.
