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meriva
3 years ago
6

How many valence electrons does group 18 have

Chemistry
2 answers:
Rus_ich [418]3 years ago
8 0

Answer:

group 18 has 8 valence electrons, that's why they are stable.

nalin [4]3 years ago
8 0

8!

Explanation:

You're looking at the very last column, right? Noble gases are known for their stability because their valence shells are full! Lucky for you, all you have to do to know the number of valence electrons is look at the column number and take ignore the 1! 16 becomes 6, 18 becomes 8.

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A green laser pointer emits light with a wavelength of 542 nm. What is the frequency of this light?
ehidna [41]
As we know that wavelength and frequency is inversely proportional to each other. Greater the wavelength smaller the frequency and vice versa.
 
Solution:


The relation between wavelength and frequency is as follow,

υ = c / λ

where
            υ = frequency = ?
            c = velocity of light = 3.0 × 10⁸ ms⁻¹
            λ = wavenumber = 542 nm = 542 × 10⁻⁹ m
Putting the given values,
    
            υ = 3.0 × 10⁸ ms⁻¹ / 542 × 10⁻⁹ m
Result:
            υ = 5.53 × 10¹⁴ s⁻¹
6 0
3 years ago
Vitamin c is known chemically by the name ascorbic acid determine the empirical formula of ascorbic acid if it is composed of 40
kow [346]

Answer:

=C_3H_4O_3

Explanation:

When percentage composition is given, and asked for the empirical formula, it is simplest to  assume 100 g of material. Thus,

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Mass H = 4.58 g.  Moles H = 4.58 g x 1 mole/1.0 g = 4.58 moles H

Mass O = 54.50 g.  Moles O = 54.50 g x 1 mole/16 g = 3.41 moles O

Now, we want to get the moles into whole numbers, so we begin by dividing all by the smallest, i.e. divide all values by 3.41.

Moles C = 3.41/3.41 = 1

Moles H = 4.58/3.41 = 1.34

Moles O = 3.41/3.41 = 1

Now, in order to get 1.34 to be a whole number we multiply it (and all others) by 3

Moles C = 1x3 = 3

Moles H = 1.34x3 = 4

Moles O = 1x3 = 3

Empirical Formula =C_3H_4O_3

3 0
3 years ago
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4 0
3 years ago
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Montano1993 [528]

Answer:

XL(toluene) = 0.77

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Explanation: see attachment

7 0
3 years ago
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Murljashka [212]

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(como ** 1 dm ^ 3 = 1 L **)

8 0
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