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zhuklara [117]
3 years ago
5

What specimen number shows spider eyes?

Chemistry
1 answer:
faust18 [17]3 years ago
4 0
Typically, most spiders possess eight eyes. However, others have as many as 12, and some don't have any. These eyes are for detecting light from dark, deciphering shapes and for gathering their prey.
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Le Châtelier’s principle states that increasing temperature favors a reaction that a. releases energy as heat. c. involves a che
Assoli18 [71]
I think the correct answer would be <span>requires energy as heat. From the Le Chatelier's principle, when a reaction needs energy to react, increasing the temperature would favor the reaction. This is called an endothermic reaction. Hope this answers the question.</span>
3 0
3 years ago
Read 2 more answers
Calculate the percent ionization of 1.60 M aqueous acetic acid solution. For acetic acid, Ka=1.8×10−5.
LekaFEV [45]

Answer:0.3348%

Explanation:

7 0
3 years ago
What is an easy way to measure the volume of an irregular shaped object?
pickupchik [31]

Answer: Water displacement

Explanation:

When you put an irregularly shaped object in a graduated cylinder, the water level rises. Subtract the original number of ml from the number of ml it was displaced, and you get its volume.

4 0
3 years ago
Susan needs to simplify the expression shown below what should be her first step
Digiron [165]
Susan should follow PEMDAS,

Parentheses
Exponents
Multiplication
Division
Addition
Subtraction,

So, the first step should be, to solve the equation in the parentheses.

I hope this helps!
5 0
3 years ago
Consider the following reaction: CO(g)+2H2(g)⇌CH3OH(g) Kp=2.26×104 at 25 ∘C. Calculate ΔGrxn for the reaction at 25 ∘C under eac
valentinak56 [21]

Answer : The value of \Delta G_{rxn} is, 8.867kJ/mole

Explanation :

The formula used for \Delta G_{rxn} is:

\Delta G_{rxn}=\Delta G^o+RT\ln Q   ............(1)

where,

\Delta G_{rxn} = Gibbs free energy for the reaction

\Delta G_^o =  standard Gibbs free energy

R = gas constant = 8.314 J/mole.K

T = temperature = 25^oC=273+25=298K

Q = reaction quotient

First we have to calculate the \Delta G_^o.

Formula used :

\Delta G^o=-RT\times \ln K_p

Now put all the given values in this formula, we get:

\Delta G^o=-(8.314J/mole.K)\times (298K)\times \ln (2.26\times 10^{4})

\Delta G^o=-24839.406J/mole=-24.83\times 10^3J/mole=-24.83kJ/mole

Now we have to calculate the value of 'Q'.

The given balanced chemical reaction is,

CO(g)+2H_2(g)\rightarrow CH_3OH(g)

The expression for reaction quotient will be :

Q=\frac{(p_{CH_3OH})}{(p_{CO})\times (p_{H_2})^2}

In this expression, only gaseous or aqueous states are includes and pure liquid or solid states are omitted.

Now put all the given values in this expression, we get

Q=\frac{(1.4)}{(1.2\times 10^{-2})\times (1.2\times 10^{-2})^2}

Q=8.1\times 10^{5}

Now we have to calculate the value of \Delta G_{rxn} by using relation (1).

\Delta G_{rxn}=\Delta G^o+RT\ln Q

Now put all the given values in this formula, we get:

\Delta G_{rxn}=-24.83kJ/mole+(8.314\times 10^{-3}kJ/mole.K)\times (298K)\ln (8.1\times 10^{5})

\Delta G_{rxn}=8.867\times 10^3J/mole=8.867kJ/mole

Therefore, the value of \Delta G_{rxn} is, 8.867kJ/mole

3 0
3 years ago
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