<h3><u>Answer;</u></h3>
B. It involves loss of electrons.
<h3><u>Explanation;</u></h3>
- Oxidation occurs when electrons are lost by an atom while reduction refers to the gain of electrons by an atom.
- <u><em>In this case, magnesium atom reacts with sulfur to form magnesium sulfide by loosing two electrons and forming magnesium ion (Mg2+). Therefore magnesium undergoes oxidation.</em></u>
- Sulfur, on the other hand will gain electrons to form Sulfide ions, therefore it undergoes reduction.
- Therefore;<em><u> In magnesium sulfide (MgS), magnesium loses two electrons and becomes a cation with a positive-two charge. Likewise, sulfur obtains the two electrons lost from magnesium and becomes an anion with a negative-two charge. However, the overall charge of MgS is zero.</u></em>
Answer:
96g
Explanation:
Given parameters:
Number of moles of NaOH = 2.4moles
Unknown:
Mass of NaOH = ?
Solution:
The mass of a substance given the number of moles can be found using the expression below;
Mass of NaOH = Number of moles x molar mass;
Molar mass of NaOH = 23 + 16 + 1 = 40g/mol
Now input the parameters and solve;
Mass of NaOH = 2.4 x 40 = 96g
Answer:
i. Keq=4157.99.
ii. More hydrogen sulfide will be produced.
Explanation:
Hello,
i. In this case, for the concentrations at equilibrium on the given chemical reaction, the equilibrium constant results:
![Keq=\frac{[H_2S]^2}{[H_2]^2[S_2]} =\frac{(0.97M)^2}{(0.051M)^2(0.087)} =4157.99](https://tex.z-dn.net/?f=Keq%3D%5Cfrac%7B%5BH_2S%5D%5E2%7D%7B%5BH_2%5D%5E2%5BS_2%5D%7D%20%3D%5Cfrac%7B%280.97M%29%5E2%7D%7B%280.051M%29%5E2%280.087%29%7D%20%3D4157.99)
ii. Now, by means of the Le Chatelier's principle, the addition of a reactant shifts the reaction towards products, it means that more hydrogen sulfide will be produced in order to reach equilibrium.
Best regards.
Explanation:
Moles of phosphorus pentachloride present initially = 2.5 mol
Moles of phosphorus trichloride at equilibrium = 0.338 mol

Initially
2.5 mol 0 0
At equilibrium:
(2.5 - x) mol x x
So, from above, the moles of phosphorus trichloride at equilibrium , x= 0.338 mol
Mass of 0.338 moles of phosphorus trichloride at equilibrium:
= 0.338 mol × 137.5 g/mol = 46.475 g
Moles of phosphorus pentachloride present at equilibrium :
= (2.5 - 0.338) mol = 2.162 mol
Mass of 2.162 moles of phosphorus pentachloride at equilibrium:
= 2.162 mol × 208.5 g/mol = 450.777 g
Moles of chloride gas present at equilibrium : 0.338 mol
Mass of 0.338 moles of chloride gas at equilibrium:
= 0.338 mol × 71 g/mol = 23.998 g
Answer:
2HNO3+Ca(OH)2 = Ca(NO3)2+2H2O
Explanation:
The reaction between Nitric acid(HNO3)and Calcium hydroxide(Ca(OH)2) gives Calcium Nitrate( Ca(NO3)2 and Water( H2O)