Answer:
None of these
Explanation:
For a reaction;
aA + bB ------>cC + dD
The equilibrium constant K is given as;
K = [C]^c [D]^d/[A]^a [B]^b
The equilibrium constant neither depends on the concentrations of the reactants nor on that of the products.
Let us recall that at equilibrium, the concentrations of reactants and products remain largely constant. This implies that, concentration of species do not appreciably change at equilibrium because the rates of forward and reverse reactions are equal.
Hence, the equilibrium constant neither depends on the initial/final concentrations of the reactants nor on the initial/final concentrations of the products.
Answer:
Of the following equilibria, only one will shift to the right in response to a decrease in volume.
On decreasing the volume the equilibrium will shift in right direction due to less number of gaseous moles on product side.
Explanation:
Any change in the equilibrium is studied on the basis of Le-Chatelier's principle.
This principle states that if there is any change in the variables of the reaction, the equilibrium will shift in the direction to minimize the effect.
Decrease the volume
If the volume of the container is decreased , the pressure will increase according to Boyle's Law. Now, according to the Le-Chatlier's principle, the equilibrium will shift in the direction where decrease in pressure is taking place. So, the equilibrium will shift in the direction number of gaseous moles are less.
On decreasing the volume the equilibrium will shift in right direction due to less number of gaseous moles on product side.
On decreasing the volume the equilibrium will shift in left direction due to less number of gaseous moles on reactant side.

On decreasing the volume the equilibrium will shift in left direction due to less number of gaseous moles on reactant side.

On decreasing the volume the equilibrium will shift in no direction due to same number of gaseous moles on both sides.

On decreasing the volume the equilibrium will shift in no direction due to same number of gaseous moles on both sides.
Answer:
4.00L
Explanation:
Using Charle's law, which have the following equation:
V1/T1 = V2/T2
Where;
V1 = initial volume (litres)
T1 = initial temperature (Kelvin)
V2 = final volume (litres)
T2 = final temperature (Kelvin)
According to the information provided, T1 = 275K, T2 = 400K, V1 = ?, V2 = 5.82L
Hence, using the formula;
V1/275 = 5.82/400
400 × V1 = 275 × 5.82
400V1 = 1600.5
V1 = 1600.5 ÷ 400
V1 = 4.001
Therefore, volume of the gas before it is heated is 4.00L
Answer:
this us a pm interesting question
Explanation:
good job