Let X = the 29% alloy and Y = the 60% alloy.
They want a total of 80kg, so you have X +Y = 80
Rewrite that to get X = 80-Y
You also want 0.20X + 0.60Y = 0.52(80)
Replace X with 80-y:
0.20(80-y) + 0.60y = 0.52(80)
Simplify:
16 - 0.20y + 0.60y = 41.6
Combine like terms:
16 +0.40y = 41.6
Subtract 16 from each side:
0.40y = 25.6
Divide both sides by 0.40
y = 25.6 / 0.40
y = 64
Now you have Y replace y with 80 in X = 80-Y
X = 80 - 64
X = 16
They need 64 Kg of the 60% alloy and 16 Kg of the 20% alloy.
8a - 4 = 25 + 6 (a - 8)
(distribute the 6)
8a - 4 = 25 + 6a - 48
(combine like terms 25 - 48)
8a - 4 = 6a - 23
( subtract 6a from both sides)
2a - 4 = -23
(add 4 to both sides)
2a = -19
(divide both sides by 2)
a = - 9.5
////CHECK/////
8 (-9.5) - 4 = 25 + 6 ( -9.5 -8)
(plug each side into a calculator)
-80 = -80
FINAL ANSWER:
a = -9.5
Answer:
a) 0.1353
b) 0.3679
Step-by-step explanation:
Let's start by defining the random variable T.
T : ''The time (in hours) required to repair a machine''
T ~ exp (λ)
T ~ exp (1)
The probability density function for the exponential distribution is
(In the equation I replaced λ = L)

With L > 0 and x ≥ 0
In this exercise λ = 1 ⇒

For a)





For b)

The event (T ≥ 10 / T > 9) is equivalent to the event T ≥ 1 so they have the same probability of occur



Answer:
36π
Step-by-step explanation:
The area of a circle is given as:

where r = radius of the circle
The area of a sector of a circle is given as:

where α = central angle in radians
Since
is the area of a circle, A, this implies that:

A circle has a sector with area 33 pi and a central angle of 11/6 pi radians.
Therefore, the area of the circle, A, is:

The area of the circle is 36π.
Answer:
3.1
4.2
5.2
42
Step-by-step explanation: They’re congruent so just copy what the other triangle has all you had to do was find the radius.