Answer:
There is significant evidence at 0.05
Step-by-step explanation:
Given that:
After performing hypothesis., with confidence level being α = 0.05 ; The researcher decides to reject the Null. The conclusion will be ;
There is significant evidence to reject the Null at confidence level of 0.05
Answer:
1, , .
Step-by-step explanation:
probability =
Total number of persons in the party = n
a) Pr ( every person gets their phone back) = Pr (each person picks his phone ) multiplied by number of person
= × n = 1.
No of first m persons to pick = m
No of last m persons to pick = 1 - m
b) Pr (first m persons to pick each gets their phones back) =
c) Pr( first m persons get a phone belonging to last m persons) =
Given:
Consider the below figure attached with this question.
∠EFH = (5x + 1)°, ∠HFG = 62°, and ∠EFG = (18x + 11)°
To find:
The measure of ∠EFH.
Solution:
From the figure it is clear that ∠EFG is divide in two parts ∠EFH and ∠HFG. So,
Isolate variable terms.
Divide both sides by 13.
The value of x is 4.
Therefore, the measure of ∠EFH is 21°.
The square root of 25 is 5, so each side is 5metres x
Answer:
23.52 miles
Step-by-step explanation:
Let us find the number of miles that they would have run.
Kana starts at 9:35 a.m. and runs at an average rate of 7 mph.
Let the time she has spent so far be t.
Speed is given as:
s = d / t
where d = distance and t = time
=> d = s * t
Therefore, for Kana:
d = 7 * t = 7t _____________(1)
Ji-Hun starts at 10:00 am (25 minutes after Hannah) and runs at an average rate of 8 mph.
25 minutes = 25/60 hour = 0.42 hour
So, his time (compared to Kana's) is t - 0.42.
therefore, for Ji-Hun:
d = 8 * (t - 0.42)
=> d = 8t - 3.36 ____________(2)
Equating (1) and (2):
7t = 8t - 3.36
=> 8t - 7t = 3.36
t = 3.36 hours
Therefore, let us find d:
d = 7 * 3.36 = 23.52 miles
So, Ji-Hun will catch up to Kana after 23.52 miles.