Answer:
Area of trapezoid:
12 + 6<-- your two bases of the trapezoid = 18
18 x 4 = 72, 72 divided by 2 = 36
now we multiply by 2 since there are 2 trapezoids:
36 x 2 = 72
Area of rectangle in front:
6 x 3 = 18
Area of the 2 rectangles on the sides:
5 x 3 = 15
(multiply by 2 since there are two rectangles on both sides)
15 x 2 = 30
Area of rectangle on the back:
12 x 3 = 36
Now lets add up all the areas:
72 + 18 + 30 + 36 = 156 in2 is your answer.
The argument is valid by the law of detachment.
Answer:
Except k=7, any real number for k would cause the system of equations to have no solution.
Step-by-step explanation:
In general a system of equations can be represented as ax+by=c and dx+ey=f. In order this system of equations to have NO SOLUTIONS a/d=b/a≠c/f. In our example a=6, b=4, c=14, d=3, e=2 and f=k. To apply the formula above, 6/3=4/2≠14/k. Hence k≠7. It can be concluded that except k=7, any real number for k would cause the system of equations to have no solutions.
Just for information, if k=7 the system will have infinitely many solutions.
They had the same quotient because both of those equations are equal
