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3 years ago

11

a scale model of a house is 1 ft long. The actual house is 50 ft long. In the model, the window is 11/5 in. high. how many feet

is the actual window height

1 answer:

Talja [164]3 years ago

5 0

Answer:

9.167

Step-by-step explanation:

11/5*50/12

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Island A is 150 miles from Island B. A ship captain travels 310 miles from Island A and then finds that he is off course and 200

wolverine [178]

Answer:

156.37°

Step-by-step explanation:

We solve this above question, using Cosine rule which is given as:

Cos C = a² + b² - c²/2ab

Let the Angle be represented as: x

Cos x = 310² + 200² - 150²/2 × 310 × 200

x = arc cos [ 310² + 200² - 150²/2 × 310 × 200]

x = 23.63°

The angle, in degrees, that he must turn through to head straight for Island B is given as:

180° - 23.63°

= 156.37°

4 0

3 years ago

Reabilwe is conducting an experiment in which the temperature is measured carefully. The temperature was 106°C at the end of the

frosja888 [35]

The formula to calculate the temperature (T) after m minutes is -

T = 106 - 6m

We have Reabilwe who is conducting an experiment in which the temperature is measured carefully. The temperature was 106°C at the end of the first minute, and then it falls by 6°C every minute after that.

We have to tp determine a formula to calculate the temperature (T) after m minutes.

<h3 /><h3>Starting from x, if the bacteria count rises by 5 every second, then determine the formula to calculate the bacteria count after 30 seconds.</h3>

Initial count = x

Count increasing per second = 5

Assume that the bacteria count after t seconds is y. Then -

y = x + 5t

for t = 30 ↔ y = 150 + x

According to question, we have -

Initial Temperature = 106 degrees Celsius

Temperature increase per minute = 6 degrees Celsius

Assume that the Temperature fall after m minutes is T. Then -

T = 106 - 6m

Hence, formula to calculate the temperature (T) after m minutes is -

T = 106 - 6m

To solve more questions on Equation Modelling, visit the link below -

brainly.com/question/20876878

#SPJ1

5 0

2 years ago

DAVID PLZ HELP LAST ONE

Leto [7]

Answer:

1.D

2.c

Step-by-step explanation:

f(m/4)=8(m²/16)-4(m/4)

=m²/2-m

f(-4)=-3(-4)²+5(-4)

=-3(16)-20

=-48-20

=-68

3 0

3 years ago

Read 2 more answers

Catron evaluates the expression (negative 9) (2 and two-fifths) using the steps below.

Vlad [161]

Answer:

Catron's error is

"She did not follow order of operations"

Step-by-step explanation:

Catron evaluates the expression (negative 9) (2 and two-fifths)

That expression can be written as below

$(-9)(2\frac{2}{5})$

Catron's error is

"She did not follow order of operations"

The corrected steps are

Step1: Given expression is $(-9)(2\frac{2}{5})$

Step2: Convert mixed fraction into improper fraction

$(-9)(2\frac{2}{5})=(-9)(\frac{12}{5})$

Step3: Multiplying the terms

$(-9)(2\frac{2}{5})=-7\frac{-108}{5}$

Therefore solution $(-9)(2\frac{2}{5})=-7\frac{-108}{5}$

6 0

3 years ago

Read 2 more answers

A lathe is set to cut bars of steel into lengths of 6 cm. The lathe is considered to be in perfect adjustment if the average len

Gnom [1K]

Answer:

$t=\frac{5.97-6}{\frac{0.4}{\sqrt{93}}}=-0.723$

E. -0.723

$df=n-1=93-1=92$

$p_v =2*P(t_{(92)}$

Since the p value is very high we don't have enough evidence to conclude that the true mean for the lengths is different from 6 cm.

Step-by-step explanation:

Information provided

$\bar X=5.97$ represent the sample mean for the length

$s=0.4$ represent the sample standard deviation

$n=93$ sample size

$\mu_o =6$ represent the value that we want to test

$\alpha=0.05$ represent the significance level

t would represent the statistic

$p_v$ represent the p value for the test

System of hypothesis

We need to conduct a hypothesis in order to check if the lathe is in perfect adjustment (6cm), then the system of hypothesis would be:

Null hypothesis: $\mu = 6$

Alternative hypothesis: $\mu \neq 6$

since we don't know the population deviation the statistic is:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

Replacing in formula (1) we got:

$t=\frac{5.97-6}{\frac{0.4}{\sqrt{93}}}=-0.723$

E. -0.723

P value

The degrees of freedom are given by:

$df=n-1=93-1=92$

Since is a two tailed test the p value would be:

$p_v =2*P(t_{(92)}$

Since the p value is very high we don't have enough evidence to conclude that the true mean for the lengths is different from 6 cm.

5 0

3 years ago