Answer:
Step-by-step explanation:
For any quadrilateral to be a parallelogram
i) either both the pairs of opposite sides must be equal
ii) Both the pairs of opposite sides must be parallel
iii) Opposite pairs of angles must be equal
iv) Diagonals must bisect each other.
v) A pair of opposite sides must be parallel and equal
Here we are already given that AB || CD
So either we should be given that AD || BC
or we must be given that AB = CD
Here it is given AB = CD as an option.
So Option A) or the first option is the right answer that AB ≅CD is needed to prove ABCD is a parallelogram.
Answer:
3x² + x - 3
Step-by-step explanation:
The way I like to do it is to get rid of the x's and just use the numbers in the case of synthetic division
Pretend the square root of the division symbol
-4 √ 3 12 1 -12
Quick note: We're dividing by -4 because we're dividing by x + 4
First bring down the 3
-4 √ 3 13 1 -12
3
Multiply it by 4 then bring add it to the next number
-4 √ 3 13 1 -12
-12
3 1
Add that number to the next one
-4 √ 3 13 1 -12
-12 -4
3 1 -3
Finally repeat the step for the last number
-4 √ 3 13 1 -12
3 -12 -4 +12
3 1 -3 0
Now take those bottom numbers and add back the x's but with one less power, so the starting x³ would now become x², x² would become x, and so on
3x² + 1x - 3
Distribute -3 to parenthasees
-3(r+9)=-3r-27
now we have
-3r-27=-32
add 27 to both sides
-3r+27-27=27-32
-3r+0=-5
-3r=-5
divide both sides by -3
r=-5/-3
r=5/3
5 buses is the answer pls mark me brainliest
Answer:
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