When 5 grams of CO and 5grams of O₂ is combined according to the reaction 2CO + O₂ ----------> 2CO₂ then Limiting reagent is CO.
Limiting reagent is the reactant that get used up in the reaction first.
According to the given reaction:
2CO + O₂ ----------> 2CO₂
5g 5g
∴ Molar mass of CO = Molar mass of C + Molar mass of O
⇒ Molar mass of CO = 14 + 16
⇒ Molar mass of CO = 28g
∴ Molar mass of O₂ = 16(2) = 32g
∴ Molar mass of CO₂ = Molar mass of C + 2(Molar mass of O)
⇒ Molar mass of CO₂ = 14 + 2(16)
⇒Molar mass of CO₂ =44g
Let's find out the moles of CO and O₂
∴ Moles = Given mass / Molar mass
⇒ moles of CO = 5/28 = 0.17
⇒ moles of O₂ = 5/32 = 0.15
For finding out the Limiting Reagent, we will divide the number of moles with the stiochiometry of the given reaction.
⇒ For CO = Moles/ stiochiometry = 0.17/2 = 0.085
⇒ For O₂ = Moles/ stiochiometry = 0.15/1 = 0.15
Since, the ratio of number of moles with the stiochiometry is less for CO hence it is the Limiting reagent, i.e. it will get used up in the reaction first.
Hence, the Limiting reagent for the reaction is CO.
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