Answer:
66.67%
Explanation:
From the given information:
mass of cyclohexane = 2.9949 grams
density of cyclohexane = 0.779 g/mL
Recall that:
Density = mass/volume
∴
Volume = mass/density
So, the volume of cyclohexane = 2.9949 g/ 0.779 g/mL
= 3.8445 mL
Also,
mass of propylbenzene = 1.6575 grams
density of propylbenzene = 0.862 g/mL
Volume of propylbenzene = 1.6575 g/ 0.862 g/mL
= 1.9229 mL
The volume % composition of cyclohexane from the mixture is:
= 66.67%
(B. 3) 172 All nonzero digits are significant.
(A. 4) 450.0 x 10^3 Trailing zeroes after the decimal point are significant.
(A. 4) 3427 All nonzero digits are significant.
(B. 3) 0.0000455 Leading zeroes are not significant.
(B. 3) 0.00456 Leading zeroes are not significant.
(C. 5) 2205.2 Zeroes between nonzero digits are significant.
(C. 5) 107.20 Trailing zeroes after the decimal point are significant.
(B. 3) 0.0473 Leading zeroes are not significant.
Entropy change is defined only along the path of an internally reversible process path.
<h3><u>What is Entropy Change </u>?</h3>
- Entropy is a measure of a thermodynamic system's overall level of disorder or non-uniformity. The thermal energy that a system was unable to use to perform work is known as entropy.
- Entropy Change is a phenomena that measures how disorder or randomness have changed inside a thermodynamic system.
- It has to do with how heat or enthalpy is converted during work. More unpredictability in a thermodynamic system indicates high entropy.
- Entropy is a state function, hence it is independent of the direction that the thermodynamic process takes.
- The rearranging of atoms and molecules from their initial state causes the change in entropy.
- This may result in a decrease or rise in the system's disorder or unpredictability, which will, in turn, result in a corresponding drop or increase in entropy.
To view more questions about entropy change, refer to:
brainly.com/question/4526346
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Answer:
Explanation:
Hello,
In this case, we can consider that the given heat of combustion is indeed the heat of reaction since it corresponds to the combustion of propane, which is computed by using the heat formation of all the involved species as shown below:
Thus, since the heat of formation of gaseous carbon dioxide is -393.5 kJ/mol, water -241.8 kJ/mol and oxygen 0 kJ/mol, the heat of formation of propane is:
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