<span>Assume
p=735 Torr
V= 7.6L
R=62.4
T= 295
PV-nRT
(735 Torr)(7.60L)= n (62.4Torr-Litres/mole-K)(295K)
0.30346 moles of NH3
Find moles
0.300L solution of 0.300 M HCL = 0.120 moles of HCL
0.30346 moles of NH3 reacts with 0.120 moles of HCL producing 0.120 moles of NH4+ ION, and leaving 0.18346 mole sof NH3 behind
Find molarity
0.120 moles of NH4+/0.300L = 0.400 M NH4+
0.18346 moles of NH3/0.300L = 0.6115 M NH3
NH4OH --> NH4 & OH-
Kb = [NH4+][OH]/[NH4OH]
1.8 e-5=[0.300][OH-]/[0.6115]
[OH-]=1.6e-5
pOH= 4.79
PH=9.21
.</span>
Nobles gases, since they all have 8 e- on their last layer of electrons.
Answer:
marine biology
coastal ecology
astronomy
meteorology
Explanation:
As a college student, to study oceanography one will have to take classes in the field of marine biology, coastal ecology, astronomy and meteorology.
An oceanographer is someone or a professional that studies the ocean in order have more scientific knowledge about them.
Oceanography is a merger of geology, biology, chemistry, physics as it pertains to the ocean.
- There is no need to study human anatomy to study oceanography.
- Marine biology and coastal ecology deals with study of life forms in their marine environment.
- Astronomy and meteorology helps to gain insight about the formation of the ocean and how weather relates to the ocean.
Answer:
It should b KNO3
Explanation:
one Potassium (K) and three Nitrite (NO3)
