Answer: A 13.88 mL of the concentrated acid would be required to make 250. mL of a 1.00 M 
solution.
Explanation:
Given: 
= 18.0 M, 
= ?
= 1.00 M, 
= 250 mL
Formula used to calculate the volume of concentrated acid is as follows.
Substitute the values into above formula as follows.
Thus, we can conclude that 13.88 mL of the concentrated acid would be required to make 250. mL of a 1.00 M solution.
The inducible isoform (NOS<span>-2) is calcium-independent and produces large amounts of </span>gas<span> that can be cytotoxic. </span>NOS<span> oxidizes the guanidine group of L-</span><span>arginine in a process that consumes </span>five<span> electrons and results in the formation of NO with stoichiometric formation of L-citrulline. </span>
Answer:
≈ 2.74 mol 
(I rounded to 3 sig figs because the starting amount has 3 sig figs.)
Explanation:
2.73736313184 mol ≈ 2.74 mol
Hope this helps!
