In such type of problems where reactant and product ratios are calculated one (Launa) should take start from balanced chemical equation. A balanced chemical equations helps in solving such problems. For this purpose chemical equation of this combustion reaction is drawn.
Equation:
C₃H₁₀ ⁺ 5 O₂ ⁻⁻⁻⁻⁻⁻⁻⁻⁻> 3 CO₂ ⁺ 4 H₂O
Now, According to this balanced equation one molecule of propane reacts with 5 molecules of oxygen to produce 3 molecules of carbon dioxide and 4 molecules of water.
As She is given with 2 molecules of propane and 10 molecules of oxygen, which means that the equation is multiplied by 2. So, the product side must also be multiplied by 2 to balance the equatio (Law of Conservation of Mass).
Result:
( C₃H₁₀ ⁺ 5 O₂ ⁻⁻⁻⁻⁻⁻⁻⁻⁻> 3 CO₂ ⁺ 4 H₂O ) ₓ 2
2 C₃H₁₀ ⁺ 10 O₂ ⁻⁻⁻⁻⁻⁻⁻⁻⁻> 6 CO₂ ⁺ 8 H₂O
So, 6 molecules of carbon dioxide and 8 molecules of water are produced.
Answer:
= 498.13 mmHg
Explanation:
Using the combined gas law;
P1V1/T1 =P2V2/T2
in this case; P1 = 725 mmHg, V1 = 375 mL and T1 = 25°C + 273 = 298 K
P2 = ? V2 = 500 mL and T2 (standard temperature) = 0°C + 273 = 273 K
P2 = P1V1T2/T1V2
= (725 × 375 × 273)/(298 × 500)
<u>= 498.13 mmHg </u>
The answer is C
Beta decay occurs when a neutron changes into a proton while emitting an electron
