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krok68 [10]
2 years ago
5

what was happening to the H20 when the lines on the graph were mostly flat? What kind of energy was being added to the system?

Chemistry
2 answers:
adelina 88 [10]2 years ago
8 0

Answer: A heating curve graphically represents the phase transitions that a substance undergoes as heat is added to it.

The plateaus on the curve mark the phase changes. The temperature remains constant during these phase transitions.

Water has a high boiling point because of the strong hydrogen bonds between the water molecules; it is both a strong hydrogen bond donor and acceptor.

The first change of phase is melting, during which the temperature stays the same while water melts. The second change of phase is boiling, as the temperature stays the same during the transition to gas

Explanation:

bearhunter [10]2 years ago
6 0

That's latent heat of vaporization.

  • Water boils at 100°C
  • The graph increases still 100°C
  • once it reaches boiling point it yields a straight line because of latent heat after all molecules are evaporated then the graph rises back
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4 0
3 years ago
Place the following elements in order of increasing electronegativity.K Cs PA. K < P < CsB. P < Cs < KC. Cs < K &
skad [1K]

Answer:

C. Cs < K < P

Explanation:

Electronegativity is the basically the tendency of an atom to attract electrons. The pauling scale is used to quantify electronegativity, the most electronegative element; fluorine has a value of 4.0 and francium, the least electronegative element has a value of 0.7

The electronegative values of the following elements are given as;

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Cs =0.79

P = 2.19

Arranging in order of increasing electronegativity, we have;

Cs < K < P. The correct option is;

C. Cs < K < P

5 0
3 years ago
When converting from moles to molecules OR molecules to moles you use what quantitative value?
miv72 [106K]
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7 0
3 years ago
A 0.753 g sample of a monoprotic acid is dissolved in water and titrated with 0.250 M NaOH. What is the molar mass of the acid i
Alexeev081 [22]

Answer:

MM_{acid}=140.1g/mol

Explanation:

Hello,

In this case, since the acid is monoprotic, we can notice a 1:1 molar ratio between, therefore, for the titration at the equivalence point, we have:

n_{acid}=n_{base} \\\\V_{acid}M_{acid}=V_{base}M_{base}\\\\n_{acid}=V_{base}M_{base}

Thus, solving for the moles of the acid, we obtain:

n_{acid}=0.0215L*0.250\frac{mol}{L}=5.375x10^{-3}mol

Then, by using the mass of the acid, we compute its molar mass:

MM_{acid}=\frac{0.753g}{5.375x10^{-5}mol} \\\\MM_{acid}=140.1g/mol

Regards.

7 0
3 years ago
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