How many grams of carbonic acid were produced by the 3.00g sample of NaHCO3

When sodium chloride reacts with iron it forms sodium and iron (ll) Chloride. Write down the balanced equation and classify it \

BartSMP [9]

Answer:

NaCl + Fe2+ ---> FeCl2 + Na+

Single replacement

Explanation:

Na is replaced by Fe2+ to form FeCl2, and that is the only replacement. Thus, it is single replacement.

7 0

3 years ago

What are the three main particles in the modern model of an atom

EastWind [94]

Protons and neutrons in the nucleus (the bit in the middle) and small tiny electrons that orbit the nucleus

7 0

2 years ago

The aldol condensation involves nucleophilic attack of an enolate to a carbonyl. Use the pop-up menus to identify the total numb

Sindrei [870]

Aldol condensation involves the reaction of an acid or base with a carbonyl group producing a nucleophile that attacks another carbonyl compound to yield a β-hydroxyaldehyde or β-hydroxyketone compound.

<h3>What is aldol condensation?</h3>

The aldol condensation is a reaction in organic chemistry in which there is a reaction between an acid or base and a carbonyl group which then serves as the nucleophile that attcks a second carbonyl to yield a β-hydroxyaldehyde or β-hydroxyketone compound.

The aldol condensation may be acid catalysed or base catlysed. The question is incomplete hence the complete mechanimsms can not be decuced.

Learn more about aldol condensation: brainly.com/question/9415260

3 0

2 years ago

4. Chemical formula, mg (Cl0₃)2

grin007 [14]

Answer:

0.017mole

0.0033M

Explanation:

Given parameters:

Formula of the compound:

Mg(ClO₃)₂

Mass of the sample = 3.24g

Unknown:

Number of moles of the sample = ?

Molarity = ?

Solution:

The number of moles of any substance is given as:

Number of moles = $\frac{mass}{volume}$

Molar mass of Mg(ClO₃)₂ = 24 + 2[35.5 + 3(16)] = 191g/mol

Number of moles = $\frac{3.24}{191}$ = 0.017mole

Molarity is the number of moles of a solute in a solution:

Molarity = $\frac{number of moles }{volume}$

Volume given = 5.08L

Molarity = $\frac{0.017}{5.08}$ = 0.0033M

5 0

3 years ago

A 100.0-mL sample of 1.00 M NaOH is mixed with 50.0 mL of 1.00 M H2SO4 in a large Styrofoam coffee cup calorimeter fitted with a

worty [1.4K]

Answer:

THE ENTHALPY CHANGE IN KJ/MOLE IS +114 KJ/MOLE.

Explanation:

Heat = mass * specific heat capacity * temperature rise

Total volume = 100 + 50 = 150 mL

Total mass = density * volume

Total mass = 1 * 150 mL = 150 g

So therefore, the heat evolved during the reaction is:

Heat = 150 * 4.18 * ( 31.4 - 22.3)

Heat = 150 * 4.18 * 9.1

Heat = 5705.7 J

Equation for the reaction:

2 NaOH(aq) + H2SO4(aq) → Na2SO4(aq) + 2 H2O(l)

From the equation, 2 moles of NaOH reacts with 1 mole of H2SO4 to produce 1 mole of Na2SO4 and 2 moles of water

50 mL of 1 M of H2SO4 contains

50 * 1 / 1000 mole of acid

= 0.05 mole of acid

The production of 1 mole of water evolved 5705.7 J of heat and hence the enthalpy changein kJ per mole will be:

0.05 mole of H2SO4 produces 5705.7 J of heat

1 mole of H2SO4 will produce 5705.7 / 0.05 J

= 114,114 J / mole

In kj/mole = 114 kJ/mole.

Hence, the enthalpy change of the reaction in kJ /mole is +114 kJ/mole.

5 0

3 years ago